<span>Three numbers can be defined as x, y, and z.
x + y + z = 64
y = x+3
z = 2x - 11
.
substitute for y and z
x + (x+3) + (2x-11) = 64
4x -8 = 64
4x = 72
x = 18
.
y = x+3 = 21
z = 2x -11 = 2(18) -11 = 36-11 = 25
.
x + y + z = 18 + 21 + 25 = 64
Correct.
.
Answer: The three numbers are 18, 21, and 25.</span>
This is a scholarship.
Student loans must be repaid; grants are given usually without those types of restrictions; and student work involves a student having an on-campus job.
|12x + 1| = 10
Remove the absolute value term and make two equations:
12x +1 = 10
12x +1 = -10
Now solve for both x values:
12x +1 = 10
Subtract 1 from both sides:
12x = 9
Divide both sides by 12:
x = 9/12
12x +1 = -10
Subtract 1 from both sides:
12x = -11
Divide both sides by 12:
x = -11/12
The answer would be (-11/12, 912)
Answer:
Normal Distribution
Step-by-step explanation: A normal distribution will generally have a bell shape. It is also called a bell curve, due to its bell shape.
It is also called Gaussian distribution. The point near the peak is where most of the observations cluster, while the values further away from the mean will be distributed equally in both directions on the curve.
Missing data:
Viewer's Age Group Excellent Good Average Poor Marginal Total
16–25 52 42 12 7 113
26–35 33 50 5 9 97
36–45 58 12 28 34 132
46–55 25 17 22 12 76
56 + 12 5 3 8 28
Marginal Total 180 126 70 70 446
A rating of good or excellent indicates the audience liked the movie, while a rating of poor indicates the audience disliked the movie.
<h3>How to determine the rating of the film from the 46–55 age group?</h3>
A movie producer accomplished a survey behind a preview screening of her latest movie to estimate how the film would be accepted by viewers from various age groups. The table displays the numbers of viewers in various age groups who ranked the film excellent, good, average, and poor.
25/446 = 0.05605
0.05605
100% = 5.605%
Out of the entire respondents, the percentage of respondents from the 46–55 age group who ranked the film excellent exists at 5.605%.
To learn more about data refer to:
brainly.com/question/4219149
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