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gavmur [86]
3 years ago
15

27^4–9^5 3^9 is divisible by 25

Mathematics
1 answer:
hichkok12 [17]3 years ago
6 0

Answer:

  no

Step-by-step explanation:

If you mean

  27^4 - 9^5·3^9 = -1161730026

it has no factors of 5, so cannot be divisible by 25.

__

If you mean ...

  (27^4 -9^5)/3^9 = ((3^3)^4 -(3^2)^5)/3^9 = 3^10(3^2 -1)/3^9 = 3(9-1) = 24

it is not divisible by 25, either.

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What is the value of x if the perimeter of both shapes is the same?
AveGali [126]

The value of x is: \frac{4}{3}

<u><em>Recall</em></u>:

Perimeter of a shape is the sum of all its sides

<em>Thus</em>:

Perimeter of the triangle = x + x +x+ 4 = 3x + 4

Perimeter of the rectangle = 2(2x) + 2(x) = 4x + 2x = 6x

We are told that the perimeter of both shapes are equal. Set both perimeters equal and solve for x.

3x + 4 = 6x

<em>Add like terms</em>

<em />4 = 6x - 3x\\4 = 3x

<em>Divide both sides by 3</em>

<em />\frac{4}{3} = x\\x = \frac{4}{3}

The value of x = \frac{4}{3}

Learn more here:

brainly.com/question/20562416

3 0
2 years ago
X/-4 =30 what is X?????
Burka [1]

-120

x/-4=30

x=30×-4

x=-120

6 0
3 years ago
These box plots show the prices for two different brands of shoes.
nignag [31]

Answer: Choice C

The interquartile range (IQR) for brand A, $10, is less than the IQR for brand B, $20.

===========================================================

Explanation:

Let's go through the answer choices one by one to see which is true and which is false. Also, we'll see which is helpful when it comes to the spread.

----------------------

Choice A

The IQR is found by subtracting the values of Q1 and Q3, which are the left and right edges of the box in that order.

For boxplot A, we have an IQR = Q3-Q1 = 80-70 = 10.

So we can immediately rule out choice A because the IQR for boxplot A is not 20, but instead it's 10.

----------------------

Choice B

The statement made in choice B is true, since the center vertical lines represent the median, but it's not useful to determine the spread. The median only tells us the center of the distribution. It doesn't tell us how spread out the distribution is.

Imagine you didn't have access to the graph. Now if you're told that the median for brand A is larger than brand B's median, then you'd probably think boxplot A is more spread out; however, the boxplot diagram shows the opposite is the case.

So again the median isn't used here. We can rule out choice B.

----------------------

Choice C

This statement is true. We subtract the box edge values to get the IQR values for each boxplot

For brand A we have IQR = Q3-Q1 = 80-70 = 10

For brand B we have IQR = Q3-Q1 = 70-50 = 20

This is the answer we're after.

The IQR is one tool we can use to measure the spread. The range is another option. We could also use the variance or the standard deviation (two slightly similar ideas) to measure the spread.

As you can see from the diagram, the larger the IQR, the more spread out the data will be.

----------------------

Choice D

This is false because earlier we've shown 10 is the IQR for brand A.

7 0
3 years ago
Convert 120 km/h to feet per second with an explanation.
balu736 [363]
1m =3.28 feet    1km= 1000m    1km=3 280 feet

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393 600/3 600=109.33feet/sec

6 0
3 years ago
The z-score associated with 95% is 1.96. If the sample mean is 200 and the standard deviation is 30, find the upper limit of the
ziro4ka [17]

Answer:

The upper limit of the 95% confidence interval is:

C.I_u = 200 + (58.8/\sqrt{n})

Step-by-step explanation:

The formula is given as:

C.I = μ ± Z*σ/\sqrt{n}

The upper limit => C.I_u = μ + Z*σ/\sqrt{n}

The lower limit => C.I_l = μ - Z*σ/\sqrt{n}

The sample size (n) is not stated in the question. Hence, we calculate the upper limit with respect to n.

The upper limit => C.I_u = 200 + 1.96*(30/\sqrt{n})

                                    = 200 + (1.96*30)/\sqrt{n}

                                    = 200 + 58.8/\sqrt{n}

5 0
3 years ago
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