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3 years ago

Heelp meeee !!!!!!!!!!

Mathematics

1 answer:

Katen [24]3 years ago

8 0

The function is in fact a polynomial and the degree of the polynomial is 7.

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Evaluate the expression 0.03^3

Vinvika [58]

The given expression is,

$0.03^3$

So, expanding we have,

$0.03^3=0.03\times0.03\times0.03=\text{0}.000027$

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11 months ago

Y=5x+2 what point at the y axis

almond37 [142]

I think to find the y - axis you should sub x=0
Therefore, y=5(0)+2
=2
Hence the answer is (0,2)

I'm sorry if this is wrong!

5 0

3 years ago

Choose the triangle that seems to be congruent to △AEC. △BFC △ABD △EFD

Mashutka [201]

Answer. Triangle ABD

Explanation: There’s no thinking in this, because you can use your eyes to look for the answer. Not all questions will have this type of question. But they do seem pretty similar to me.

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2 years ago

For f(x) = 4x +1 and g(x) = x2 -5, find (f 3)(x).

Georgia [21]

D!! It’s super easy I hope you can learn how to do it

4 0

3 years ago

Write an equation that is perpendicular to and 3x+y=3 whose y-intercept 5. Anyone please help me, no link just explain how to do

Liula [17]

Answer:

$y = \frac{1}{3}x + 5$

Step-by-step explanation:

By definition, two lines are perpendicular if and only if their slopes are negative reciprocals of each other: $m = - \frac{1}{m_{2} }$ , or equivalently, $m_{1} * m_{2} = -1$ .

Given our linear equation 3x + y = 3 (or y = -3x + 3):

We can find the equation of the line (with a y-intercept of 5) that is perpendicular to y = -3x + 3 by determining the negative reciprocal of its slope, -3, which is $\frac{1}{3}$ .

To test whether this is correct, we can take first slope, $m_{1} = -3$ , and multiply it with the negative reciprocal slope $m_{2} = \frac{1}{3}$ :

$m_{1} * m_{2} = -1$

$-3 * \frac{1}{3} = -1$

Therefore, we came up with the correct slope for the other line, which is $\frac{1}{3}$ .

Finally, the y-intercept is given by (0, 5). Therefore, the equation of the line that is perpendicular to 3x + y = 3 is:

$y = \frac{1}{3}x + 5$

7 0

3 years ago