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Lynna [10]
3 years ago
10

Zachary purchased a computer for 1800 on a payment plan. Three months after he purchased the computer, his balance was 1350. Fiv

e months after he purchased the computer, his balance was 1050. What is an equation that models the balance b after m months. What does the slope signify is zacharys equation?
Mathematics
1 answer:
zubka84 [21]3 years ago
3 0

<u>Solution-</u>

Zachary purchased a computer for 1800 on a payment plan.  (Initial Money)

3 months after he bought the computer, his balance was 1350. (Money after 3 months)

Total money paid in 3 months = 1800-1350 = 450

Money paid per month = 450/3 = 150

5 months after he bought the computer, his balance was 1050.

Total spent = 1800-1050 = 750 = (5× 150)

So the equation that models the balance b after m months,

b = 1800 - m(150)

∴ Here, the slope signifies the constant monthly deduction of $150.


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Deja has two baskets of berries. One of the baskets has 3 3/8 pounds of berries and the other basket has 2 7/8 pounds of berries
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Answer:

(b) The number of pounds of berries each person would receive is 1\frac{5}{8}pounds.

Step-by-step explanation:

The amount of berries in first basket = 3 3/8 pounds

Now, 3\frac{3}{8}  = 3+\frac{3}{8} = 3 + 0.375 = 3.375

So, the amount of berries in first basket = 3.375 pounds

The amount of berries in second basket = 2 7/8 pounds

Now, 2\frac{7}{8}  = 2+\frac{7}{8} = 2 + 0.875 = 2.875

So, the amount of berries in second basket = 2.875 pounds

Now, the total berries = Berries in ( First + Second)  basket

                                      = 3.375 pounds +  2.875 pounds  

                                    = 6.25 pounds

So, the number of pounds each person would have = \frac{\textrm{Total weight of viable berries}}{\textrm{4}}  = \frac{6.25}{4} = 1.5625

Now, 1.5625 = 1 + 0.5625  = 1 + \frac{5625}{10000}  = 1 + \frac{5}{8}  = 1\frac{5}{8}

So, the number of pounds of berries each person would receive is 1\frac{5}{8}pounds.

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The owner of an automobile insures it against damage by purchasing an insurance policy with a deductible of 250. In the event th
choli [55]

Answer:

Step-by-step explanation:

From the given information:

The uniform distribution can be represented by:

f_x(x) = \dfrac{1}{1500} ; o \le x \le   \  1500

The function of the insurance is:

I(x) = \left \{ {{0, \ \ \ x \le 250} \atop {x -20 , \ \  \ \ \ 250 \le x \le 1500}} \right.

Hence, the variance of the insurance can also be an account forum.

Var [I_{(x}) = E [I^2(x)] - [E(I(x)]^2

here;

E[I(x)] = \int f_x(x) I (x) \ sx

E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250) \ dx

= \dfrac{1}{1500 } \dfrac{(x - 250)^2}{2} \Big |^{1500}_{250}

\dfrac{5}{12} \times 1250

Similarly;

E[I^2(x)] = \int f_x(x) I^2 (x) \ sx

E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250)^2 \ dx

= \dfrac{1}{1500 } \dfrac{(x - 250)^3}{3} \Big |^{1500}_{250}

\dfrac{5}{18} \times 1250^2

∴

Var {I(x)} = 1250^2 \Big [ \dfrac{5}{18} - \dfrac{25}{144}]

Finally, the standard deviation  of the insurance payment is:

= \sqrt{Var(I(x))}

= 1250 \sqrt{\dfrac{5}{48}}

≅ 404

4 0
2 years ago
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