9, 9(2)=18, 9(3)=27, 9(4)=36 9(5)=45
9,18,27,36,45……..144
Not sure if this is what you are looking for. If the number of blanks is the amount of numbers allowed then the above will not work
9(13)=117, 9(14)=126, 9(15)= 135, 144
If you can only have 3 blanks then the second one could work.
Again, not sure if this is what you need. But hopefully it helps.
1) x'=(3+i√7)/2 & x"=(3-i√7)/2 No real roots.
2) x'=(-2+√14)/2 & x"=(-2-√14)/2
3) x' x" -4
Answer: B
Step-by-step explanation:
I hope you understand feel free to ask
Answer:
The zeros are 0, 4, 6.
The y-intercept is 0.
Step-by-step explanation:
f(x) = x^3 - 10x^2 + 24x
x^3 - 10x^2 + 24x = 0
x(x^2 - 10x + 24) = 0
x(x - 4)(x - 6) = 0
x = 0 or x - 4 = 0 or x - 6 = 0
x = 0 or x = 4 or x = 6
y-intercept:
Since x = 0 is a root, that means that the point (0, 0) is part of the function. That makes the y-intercept 0.
You can also solve for the y-intercept by letting x = 0 in the function and solving for f(0).
Let x = 0.
f(0) = 0^3 - 10(0^2) + 24(0)
f(0) = 0
y-intercept: 0