Answer:
Step-by-step explanation:
The value in the sequence closest to 300 is 310
<h3>Arithmetic Sequence</h3>
Arithmetic sequence is a sequence where each term increases or decreases by addition or subtraction of a constant term
the first term a = 30
common difference, d = 40
which term is closest to 300 we solve like this
300 / 40 = 7.5 say 7
the 7th term, T7 is solved by
T7 = a + ( n - 1 ) d
T7 = 30 + ( 7 - 1 ) 40
T7 = 30 + 240
T7 = 270
checking for the 8th term to confirm the nearest
T8 = T7 + d = T7 + 40
T8 = 270 + 40
T8 = 310
therefore the 8th term is closest and the value is 310
Read more on Arithmetic sequence here:
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The answer is that y is -3 and x is 0
Based on the given values above, here is the solution to find if how many ants there will be after 10 weeks and 20 weeks.
Since the population increases by 12%. we need to get 12% of the population every week.
500 x .12 = 60.
1st week = 560
2nd week = 627.2
3rd week = 702. 46
4th week = 786.76
5th week = 881. 17
6th week = 986.91
7th week= 1,105.34
8th week= 1,237.98
9th week= 1, 386.54
10th week = 1, 552.92
11th week = 1,739.27
12th week = 1,947.98
13th week= 2,181.74
14th week=2, 443.55
15th week = 2,736.76
16th week = 3, 065. 17
17th week = 3,432.99
18th week= 3,844.95
19th week= 4,306.34
20th week = 4,823.10
Therefore, after 10 weeks, there will be 1,553 ants and after 20 weeks, there will be 4,823 ants.
13 x 17n - 13 x 15
= 221n - 195