Xy = 6
x + y = 9
x + y = 9
x - x + y = -x + 9
y = -x + 9
xy = 6
x(-x + 9) = 6
x(-x) + x(9) = 6
-x² + 9x = 6
-x² + 9x - 6 = 0
-1(x²) - 1(-9x) - 1(6) = 0
-1(x² - 9x + 6) = 0
-1 -1
x² - 9x + 6 = 0
x = -(-9) ± √((-9)² - 4(1)(6))
2(1)
x = 9 ± √(81 - 24)
2
x = 9 ± √(57)
2
x = 4.5 ± 0.5√(57)
x + y = 9
4.5 ± 0.5√(57) + y = 9
- (4.5 ± 0.5√(57)) - (4.5 ± 0.5√(57))
y = 4.5 ± 0.5√(57)
(x, y) = (4.5 ± 0.5√(57), 4.5 ± 0.5√(57))
The two numbers that multiply to 6 and add up to 9 are 4.5 ± 0.5√(57).
A) If you have 12 dogs and cats (I assume 12 in total) and divide those by two, you get six dogs and six cats. It has to be more dogs than cats, and the sum of those two has to be twelve. So to reach the sum 12, while one number is bigger that the other, the number has to be 7 or more.
Answer:
Assume that the formula is true for the (k+1)term
Step-by-step explanation:
I learned this in class a couple weeks ago in intermediate algebra
Divide both sides by 2
i<3u
