P5
From Z tables and at P5 = 5% = 0.05, Z = -1.645
Therefore,
True value = mean +Z*SD = 24.1+(-1.645*2.1) = 20.6455 Chips per cookie
P95
From Z table and at P95=95%=0.95, Z= 1.645
Therefore,
True value = 24.1 +(1.645*2.1) = 27.5545 Chips per cookie
These values shows the percentages of amount of chips in the cookies. Thus, the more the percentage considered, the more the amount of chips in the cookies. This can be used to control the number of chips in cookies during production.
You'll see how to set up a table, choose appropriate x-values, plug those values into the equation.
7 9/12 = 7.75
2 11/12 = 2.917
So we can round both of these up.
7.75 rounds to 8
2.917 rounds to 3
8 + 3 = 11
So the estimated sum is 11.
7 9/12 + 2 11/12 = 10 2/3
So the actual sum is 10 2/3.
The estimated sum is a pretty good estimate to the original number.
The answer is C) 3 x 10^4
Answer:
2, 3 , 5, 7
Step-by-step explanation:
2(x - 2)/3 < (x + 1)/2 < 3(5x + 6)/4
Considering:
2(x - 2)/3 < (x + 1)/2
<=>(2x - 4)/3 < (x + 1)/2
<=> (2x - 4)*2 < (x + 1)*3
<=> 4x - 8 < 3x + 3
<=> 4x - 3x < 8 + 3
<=> x < 11
Considering:
(x + 1)/2 < 3(5x + 6)/4
<=>(x + 1)/2 < (15x + 18)/4
<=>(x + 1)*4 < (15x + 18)*2
<=> 4x + 4 < 30x + 36
<=> 4x - 30x < 36 - 4
<=> -26x < 32
<=> 26x > -32
<=> x > -32/26
=> -32/26 < x < 11
The prime numbers satisfy the above inequalities: 2, 3 , 5, 7
