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4 years ago

What number is halfway between 15 and 37

Mathematics

2 answers:

iren2701 [21]4 years ago

5 0

( 15 + 37 )÷2 = 52÷2 = 26.

tino4ka555 [31]4 years ago

5 0

$(15+37)=52/2=\boxed{26}$

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Rob is cooking a cake.The recipe calls for 9 cups of flour.He has already put in 3 cups. How many more cups does he need to put

svetoff [14.1K]

Answer:

9-3= 6 Cups

Step-by-step explanation:

Recipe needs 9 cups of flour, Rob has added 3 cups already so he needs to add 6 more cups to make it 9 cups.

7 0

3 years ago

Minimize the objective function P = 45x + 48y for the given constraints.

BabaBlast [244]

Answer:

Following are the solution to the given equation:

Step-by-step explanation:

The graph file and correct question are defined in the attachment please find it.

According to the linear programming principle, we predict, that towards the intersections of the constraint points in the viability area, and its optimal solution exists. The sketch shows the points that are (0,16), (3,1), and (6,0).

by putting each point value into the objective function:

$\to P(0,16) = 768\\\\\to P(3,1) = 183\\\\\to P(6,0) = 270$

Thus, the objective of the function is reduced with a value of 183 at (3,1).

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3 years ago

Solve the equation 2cosA = 3tanA

zavuch27 [327]

$\bf sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)
\\\\\\
tan(\theta)=\cfrac{sin(\theta)}{cos(\theta)}\\\\
-----------------------------\\\\

2cos(A)=3tan(A)\implies 2cos(A)=3\cfrac{sin(A)}{cos(A)}
\\\\\\
2cos^2(A)=3sin(A)\implies 2[1-sin^2(A)]=3sin(A)
\\\\\\
2-2sin^2(A)=3sin(A)\implies 2sin^2(A)+3sin(A)-2$

$\bf \\\\\\
0=[2sin(A)-1][sin(A)+2]\implies 
\begin{cases}
0=2sin(A)-1\\
1=2sin(A)\\
\frac{1}{2}=sin(A)\\\\
sin^{-1}\left( \frac{1}{2} \right)=\measuredangle A\\\\
\frac{\pi }{6},\frac{5\pi }{6}\\
----------\\
0=sin(A)+2\\
-2=sin(A)
\end{cases}$

now, as far as the second case....well, sine of anything is within the range of -1 or 1, so -1 < sin(A) < 1

now, we have -2 = sin(A), which simply is out of range for a valid sine, so there's no angle with such sine

so, only the first case are the valid angles for A

8 0

3 years ago

Help me please thank you

docker41 [41]

After I read the equation, I remembered that anything to the power of 1 is itself. so f(x)=2-9

2-9= -7

therefore, f(x)= -7

if x=1, then the f(x) must be Y

<u><em>therefore, your answer should be y= -7</em></u>

6 0

3 years ago

HELP PLZ DUE RN BRAINIEST TO WHOEVER RIGHT

Blizzard [7]

Answer:

solutions at -1 and 11

Step-by-step explanation:

(-b ± √b²-4ac) / 2a

in this problem, a = 1, b = -10, c = -11

(10±√100-4(-1)(-11)) / 2(1) =

(10 + √144) / 2 = 22/2 = 11

(10 - √144) / 2 = -2 / 2 = -1

3 0

3 years ago