Answer:
Explanation:
First case
A cart speed is 0.3m/s. i.e the initial velocity is u=0.3m/s
It collide with a stationary body, then after collision the ball rebounds and move in opposite direction. This shows that the ball have a velocity after impulse let say v
Then, impulse is given as the change in linear momentum of a body
Impulse =m∆v
I=m(v-u)
Note, momentum is a vector quantity.
I=m(v--u)
I=m(v+u)
I=m(v+0.3)
I¹=0.3m+mv. Equation 1
Second case
A cart speed is 0.3m/s. i.e the initial velocity is u=0.3m/s
It collide with a stationary body, then after collision the ball is at rest, this show that the final velocity is v=0
Then, impulse is given as the change in linear momentum of a body
Impulse =m∆v
I=m(v-u)
Note, momentum is a vector quantity.
I=m(v--u)
I=m(v+u)
In this case v=0 u=0.3m/s
I=m(0+0.3)
I²=0.3m. Equation 2
If we compare impulse 1 (I¹) to impulse 2 (I²)
Subtract equation 2 from 1
We have, I¹ - I² =0.3m+mv -0.3m
I¹ - I² =mv
I¹ =mv+I²
We notice that the first impulse (I¹) is greater than second impulse (I²) by mv.
The correct answer is A
