The answer is:
-when Jackhammer is a huge hammer used to breaking up the hard rocks and the hard materials to smaller pieces.
-and the metamorphic rocks are type of rocks which change to metamorphic rock by heating and high pressure so, the chemical and physical properties of the rock will be changed.
-and here in cause of using the Jackhammer there is no change in the chemical or physical properties of the original rock and no high temp(more than 200°C ) or high pressure to change to metamorphic rock . It is just a breaking up of the rock to small parts.
One side will be uneven and fall farther than the other side.
Life style are habits and standards that shape how you live
Do you remember the general equation for the distance covered
by a moving object ? There are not many perfect opportunities to
use it in all its glory, but I think this is one of them.
Position =
(starting distance) + (starting speed) (time) + (1/2) (acceleration) (time)²
H = starting position + (starting speed x t) + 1/2 A t²
Here's how we can use it, with some careful definitions:
-- Let's say the surface of the sea is zero height.
Then 'H' ... the position at the end ... is zero, when it plunks into the water, and
the starting, original position of the stone is +10 on the cliff in the man's hand.
-- Starting speed is +5 ... 5 m/s upward, when he tosses it.
-- Acceleration is 9.8 m/s² downward ... the acceleration of gravity.
I think this is going to work out just beautifully !
0 = (5) + 5t - 1/2 (9.8) t²
-4.9 t² + 5t + 5 = 0 That's the whole thing right there. Look how gorgeous that is !
Solve it for 't' with the quadratic equation,
A = -4.9
B = 5
C = 5
When you solve a quadratic with the formula, you always get two roots.
If it's a real-world situation, one of them might not make sense. That's
the result in this case.
The two roots are
t = - 0.622 second
and
t = + 1.642 second
The first one isn't useful, because it means 0.622 second <u>before</u> the man
tossed the stone up.
So our answer is: We hear the 'plunk' <em>1.642 second</em> after the upward toss.
Answer:
The maximum emf that can be generated around the perimeter of a cell in this field is
Explanation:
To solve this problem it is necessary to apply the concepts on maximum electromotive force.
For definition we know that
Where,
N= Number of turns of the coil
B = Magnetic field
Angular velocity
A = Cross-sectional Area
Angular velocity according kinematics equations is:
Replacing at the equation our values given we have that
Therefore the maximum emf that can be generated around the perimeter of a cell in this field is