Answer:
a) The trajectory will be a helical path.
b) θ = 2*π rad
Explanation:
a) Since the initial velocity of the particle has a component parallel (x-component) to the magnetic field B
, the trajectory will be a helical path.
b) Given
t = 2*π*m/(q*B)
We can use the equation
θ = ω*Δt
where
θ is the angular displacement
ω is the angular speed, which is obtained as follows:
ω = q*B/m
then we have
θ = (q*B/m)*2*π*m/(q*B)
⇒ θ = 2*π rad
In liquids, molecules particles are close together but move in random directions.
In solids, they are closely packed together and they vibrate a little.
In gases, they love around really quickly and are farther apart (even more than liquids).
Answer:
v =7.1 m/s
Explanation:
Given that
u = 3.35 m/s
t= 5 s
a= 0.75 m/s²
The final velocity = v
We know v = u +at
v=final velocity
u=initial velocity
Now by putting the values in the above equation
v = 3.35 + 0.75 x 5 m/s
v =7.1 m/s
Therefore the final velocity will be 7.1 m/s
Answer:
A bear normally has a short, thick neck, a rounded head, a pointed muzzle, short ears, and small eyes. Some species have round faces. Bears have poor eyesight, and most have only fair hearing.
Explanation:
Modern Bears are characterized with large body and stocky legs, a long snout, shaggy hair, plantigrade paws with five non-retractile claws and a short tail.
Grizzly bears (Ursus arctos horribilis) have concave faces, a distinctive hump on their shoulders, and long claws about two to four inches long. Both the hump and the claws are traits associated with a grizzly bear's exceptional digging ability. Grizzlies are often dark brown, but can vary from blonde to nearly black.
The brown bear has a slight hump above its shoulder, round ears, a long snout and big paws with long, curved claws that it uses for digging. Unlike the black bear, it can't climb trees. It can weigh between 350-1,500 pounds. When standing on its hind legs it can be up to 5 feet tall.
Hope this helps :)
(I didn't know which type of bear so i did brown bear and grizzly bear)
Answer:
Ф = 2.179 eV
Explanation:
This exercise has electrons ejected from a metal, which is why it is an exercise on the photoelectric effect, which is explained assuming the existence of energy quanta called photons that behave like particles.
E = K + Ф
the energy of the photons is given by the Planck relation
E = h f
we substitute
h f = K + Ф
Ф= hf - K
the speed of light is related to wavelength and frequency
c = λ f
f = c /λ
Φ = 
let's reduce the energy to the SI system
K = 0.890 eV (1.6 10⁻¹⁹ J / 1eV) = 1.424 10⁻¹⁹ J
calculate
Ф = 6.63 10⁻³⁴ 3 10⁸/405 10⁻⁹ -1.424 10⁻¹⁹
Ф = 4.911 10⁻¹⁹ - 1.424 10⁻¹⁹
Ф = 3.4571 10⁻¹⁹ J
we reduce to eV
Ф = 3.4871 10⁻¹⁹ J (1 eV / 1.6 10⁻¹⁹ J)
Ф = 2.179 eV
