The magnitude of magnitude force on the proton is 2.4 x 10⁻¹² N.
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Magnitude of magnetic force on the proton</h3>
The magnitude of magnitude force on the proton is calculated as follows;
F = qvB sinθ
where;
- q is the charge of the proton
- v is the speed of the proton
- B is the magnitude of the magnetic filed
- θ is the angle between the field and speed
Substitute the given parameters and solve for the magnetic force.
F = (1.6 x 10⁻¹⁹) x (3 x 10⁶) x (5) X(sin90)
F = 2.4 x 10⁻¹² N
Thus, the magnitude of magnitude force on the proton is 2.4 x 10⁻¹² N.
Learn more about magnetic force here: brainly.com/question/13277365
Because they are placed in different habitable zones
Answer:
a) 4.9W b) 3.82W
Explanation:
Stefan-Boltzmann law of radiation formulae:
Q/t (W) = sigma* e*A*T^4
Sigma = 5.67*10^-8 j/sm^2K^4 (Stefano Boltzmann constant)
e = emissivity
T = absolute temperature in kelvin and A = area in m^2
a) Q/t = 140/10000(m^2) * 0.87* 5.67* 10^-8* (290^4) = 4.9W
b) without hair the
Q/t = 140/ 10000(m^2) *0.68* 5.67* 10^-8* (290^4)
= 3.82W
Answer:
Free body diagram
Explanation:
A free body diagram shows all the forces acting on a body. Since force is a vector quantity, the magnitude and direction of the forces are shown in the free-body diagram.
Force is the push or pull on a body.
It can be via contact or without contact. Such non-contact forces acts via a force field.
In physics, this free body diagram is used extensively.
I think 42… sorry if its wrong :( hope it helps..
