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rosijanka [135]
3 years ago
13

High-energy particles are observed in laboratories by photographing the tracks they leave in certain detectors; the length of th

e track depends on the speed of the particle and its lifetime. A particle moving at 0.993c leaves a track 1.15 mm long. What is the proper lifetime of the particle
Physics
1 answer:
murzikaleks [220]3 years ago
4 0

Answer:

Lifetime = 4.928 x 10^-32 s  

Explanation:

(1 / v2 – 1 / c2) x2 = T2

T2 = (1/ 297900000 – 1 / 90000000000000000) 0.0000013225

T2 = (3.357 x 10^-9 x 1.11 x 10^-17) 1.3225 x 10^-6

T2 = (3.726 x 10^-26) 1.3225 x 10^-6 = 4.928 x 10^-32 s  

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Two pickup trucks each have a mass of 2,000 kg. The gravitational force between the trucks is 3.00 × 10-5 N. One pickup truck is
levacccp [35]

Answer:

New gravitational force would be: 4.5\,\,\,10^{-5}\,\,\,N

Explanation:

Recall the general form of the gravitational force between two objects of masses m1 and m2 separated a distance "d":

F_g=G\,\frac{m1\,*\, m2}{d^2}

which for the 2000 kg trucks becomes:

F_g=G\,\frac{m1\,*\, m2}{d^2} \\3\,\,\,10^{-5}\,N=G\,\frac{2000\,*\, 2000}{d^2}

when we add 1000 kg of bricks to one truck, we get the following unknown force (x) that we need to find:

F_g=G\,\frac{m1\,*\, m2}{d^2} \\x=G\,\frac{3000\,*\, 2000}{d^2}

Now we divide term by term the last equation by the previous one, in order to cancel out common factors to both equation (G, d^2) and get the following equation:

\frac{x}{3\,\,\,10^{-5}} =\frac{3000}{2000} \\x=\frac{9}{2} \,10^{-5} =4.5\,\,\,10^{-5}\,\,\,N

8 0
3 years ago
Hi can someone pls answer the question number 2 pls i srsly need it. thank u :) ​
Anvisha [2.4K]

<em>The distance between the image and its leans is 19.04 cm...</em>

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5 0
2 years ago
Read 2 more answers
1. What is the kinetic Energy of a 1500kg object moving at 21 m/s?
Wewaii [24]
The formula for working out kinetic energy is

=122

KE = kinetic energy
m = mass of a body
v = velocity of a body


kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. For example, if a an object with a mass of 10 kg (m = 10 kg) is moving at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s2.

For the first one I think :
Answer:
KE = 330750 J

I’m not sure about the second one- sorry

The third is
Answer:
KE = 41454 J

Hope it helps and it is correct, sorry if it isn’t !
8 0
3 years ago
To prevent dehydration when exercising on hot and humid days it is vital to:
Nostrana [21]
Drink water before, during, and after your exercise activity! i would rlly appreciate brainliest:D
8 0
3 years ago
Read 2 more answers
How many photons are absorbed during the dental x-ray?
MariettaO [177]
<span>E=hc/wav. len
E = (6.62 x 10^-34 x 3 x 10^8)/0.0275 x 10^-9
E = 7.22182 x 10^-15 J
To convert to eV divide by 1.6 x 10^-19
E = 7.22182 x 10^-15/1.6 x 10^-19 eV
E =45.36 x 10^3 eV
Th energy, E, of a single x-ray photon in eV is = 45.36keV.

Number of photons, n = total energy/ energy of photon
n = 3.85 x 10^-6/7.22182 x 10^-15
n = 5.33 x 10^8 photons </span>
8 0
3 years ago
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