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3 years ago

More recent findings of children with exceptionally high IQs _

Physics

1 answer:

Alenkasestr [34]3 years ago

5 0

Answer:

Explanation:

Researchers and educators differ in how they define gift-

edness. Traditionally, researchers have defined giftedness

as high general intelligence as measured by a high global

IQ score (Hollingwort

Exceptionally intelligent students (hereafter referred to

as gifted students) face a variety of problems in ordinary

classrooms. They often are ostracized as being different

and weird and are labeled as nerds and geeks (Silverman,

1993a, 1993b). In addition, they face the problem of

boredom due to lack of an appropriate level of challenge

(Csikszentmihalyi, Rathunde, & Whalen, 1993; Gross,

1993). Teachers often make little accommodation to the

needs of these children, and many teachers have little

or no special training in how to teach such exceptional

children

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The membrane of a living cell can be approximated by a parallel-plate capacitor with plates of area 4.50×10−9 m2 , a plate separ

Marizza181 [45]

The energy stored in the membrane is $6.44\cdot 10^{-14} J$

Explanation:

The capacitance of a parallel-plate capacitor is given by

$C=\frac{k\epsilon_0 A}{d}$

where

k is the dielectric constant of the material

$\epsilon_0$ is the vacuum permittivity

A is the area of the plates

d is the separation between the plates

For the membrane in this problem, we have

k = 4.6

$A=4.50\cdot 10^{-9} m^2$

$d=8.1\cdot 10^{-9} m$

Substituting, we find its capacitance:

$C=\frac{(4.6)(8.85\cdot 10^{-12})(4.50\cdot 10^{-9})}{8.1\cdot 10^{-9}}=2.26\cdot 10^{-11} F$

Now we can find the energy stored: for a capacitor, it is given by

$U=\frac{1}{2}CV^2$

where

$C=2.26\cdot 10^{-11} F$ is the capacitance

$V=7.55\cdot 10^{-2} V$ is the potential difference

Substituting,

$U=\frac{1}{2}(2.26\cdot 10^{-11} F)(7.55\cdot 10^{-2})^2=6.44\cdot 10^{-14} J$

Learn more about capacitors:

brainly.com/question/10427437

brainly.com/question/8892837

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#LearnwithBrainly

6 0

3 years ago

Without an atmosphere, the equatorial curve would show minimum daily values on the solstices in June when the sub-solar point is

lapo4ka [179]

Without an atmosphere, the equatorial curve would show minimum daily values on the solstices in June when the sub-solar point is located at 23.5°N and in December when the sub-solar point is at 23.5°S latitude.

Explanation:

At the sub-solar point, the sun strikes directly at the surface with an angle of 90 degrees at a given point.

Solistice refers to that point in time when the sun’s zenith is located at the farthest point from the equator.

During summer solistice on June 21, the sun’s zenith reaches northernmost point, sub-solar point is fixed at 23.5°S Tropic of Cancer making the earth tilt 23.4 degrees

During winter soliscitse on December 21, the sub-solar point is fixed at) Tropic of Capricorn.

3 0

3 years ago

The moment of inertia of a thin uniform rod of mass M and length L about an Axis perpendicular to the rod through its Centre is

sleet_krkn [62]

Answer:

I = I₀ + M(L/2)²

Explanation:

Given that the moment of inertia of a thin uniform rod of mass M and length L about an Axis perpendicular to the rod through its Centre is I₀.

The parallel axis theorem for moment of inertia states that the moment of inertia of a body about an axis passing through the centre of mass is equal to the sum of the moment of inertia of the body about an axis passing through the centre of mass and the product of mass and the square of the distance between the two axes.

The moment of inertia of the body about an axis passing through the centre of mass is given to be I₀

The distance between the two axes is L/2 (total length of the rod divided by 2

From the parallel axis theorem we have

I = I₀ + M(L/2)²

5 0

3 years ago

A car is traveling with a velocity of 5.5 m/s and has a mass of 1200 kg. What is the kinetic energy?!

vesna_86 [32]

Answer:

Explanation:

The kinetic energy of the car can be found by using the formula

$k = \frac{1}{2} m {v}^{2} \\$

m is the Mass

v is the velocity

From the question we have

$k = \frac{1}{2} \times 1200 \times {5.5}^{2} \\ = 600 \times 30.25$

We have the final answer as

Hope this helps you

3 0

3 years ago

Two charged objects separated by some distance attract each other. If the charges on both objects are doubled with no change in

Serggg [28]

Answer:

(a) The force between them quadruples

Explanation:

According to coulomb's law, initial force between the two charged objects is given as;

$F_1=\frac{Kq_1q_2}{r^2}$

where;

k is coulomb's constant

q₁ is the charge on the first object

q₂ is the charge on the second object

r is the distance between the two objects

When the charges on both objects are doubled, then;

q₁ = 2q₁

q₂ = 2q₂

Force between the two charged objects will become

$F_2 = \frac{K2q_12q_2}{r^2} = \frac{4Kq_1q_2}{r^2} = 4(\frac{Kq_1q_2}{r^2}) = 4F_1$

Therefore, the force between them quadruples

4 0

3 years ago