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3 years ago

7

Please help me, I'm trying to find total surface area!

1 answer:

4vir4ik [10]3 years ago

5 0

Find the total surface area of the solid.

The faces of this solid are

1 rectangle 8 cm × 20 cm;

1 rectangle 17 cm × 20 cm;

1 rectangle 15 cm × 20 cm;

2 triangular bases (right triangles). The area of each one is

(8 cm × 15 cm)/2.

Total surface area:

A = 8 × 20 + 17 × 20 + 15 × 20 + 2 × [ (8 × 15)/2 ]

A = 160 + 340 + 300 + 120

A = 920 cm^2 <——<span>— this is the answer.

I hope this helps. =)
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Please help me!!! This is due at 11:59pm

Amanda [17]

Answer:

Step-by-step explanation:

they are saying when -49 = -12x +47 what is x

so solve for x

-49-47 = -12x

-96 = -12x (b/c there are two negative signs they cancel out )

$\frac{96}{12}$ =x

8 = x

:) so when you input an 8 you get out a -49

5 0

3 years ago

Simplify the polynomial (4n² + 3n – 5) − (2n² + 3n<br> -<br> + 6)

Veseljchak [2.6K]

Answer:

2n² + 1

Step-by-step explanation:

Given polynomial:

(4n² + 3n – 5) − (2n² + 3n - 6)

Solution:

Removing parentheses,we obtain

$4n {}^{2} + 3n - 5 - 2n {}^{2} - 3n + 6$

Combine like terms:

$4n { }^{2} - 2n {}^{2} + 3n - 3n - 5 + 6$
$2n { }^{2} + 0 + 1$
$\boxed{2n {}^{2} + 1}$

Done!

Order:BPEMDAS

7 0

2 years ago

Please help i need this quick ill give brainlyiest

PIT_PIT [208]

What the that needs to be solved

3 0

2 years ago

What does this equal? I keep getting different answers every time I try it.

bija089 [108]

Answer:

19/6 ...or... 3.16 repeating

Step-by-step explanation:

4 5/8 + 2/3 = 19/6

5 0

3 years ago

An object is propelled upward from the top of a 300 foot building. The path that the object takes as it falls to the ground can

serg [7]

Answer:

As per the statement:

The path that the object takes as it falls to the ground can be modeled by:

h =-16t^2 + 80t + 300

where

h is the height of the objects and

t is the time (in seconds)

At t = 0 , h = 300 ft

When the objects hit the ground, h = 0

then;

-16t^2+80t+300=0

For a quadratic equation: ax^2+bx+c=0 ......[1]

the solution for the equation is given by:

$x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$

On comparing the given equation with [1] we have;

a = -16 ,b = 80 and c = 300

then;

$t= \frac{-80\pm \sqrt{(80)^2-4(-16)(300)}}{2(-16)}$

$t= \frac{-80\pm \sqrt{6400+19200}}{-32}$

$t= \frac{-80\pm \sqrt{25600}}{-32}$

Simplify:

$t = -\frac{5}{2}$ = -2.5 sec and $t = \frac{15}{2}$ = 7.5 sec

Time can't be in negative;

therefore, the time it took the object to hit the ground is 7.5 sec

8 0

3 years ago