Typical oxidation states of copper are
C u + l, and C U +I l cuprous and cupric ions.
Divide by the atomic mass of iron. Look at your periodic table.
<span>About 11 moles. 1 mole of iron contains 6.022 * 10^23 atoms of iron.</span>
It is 3 moles. Don't doubt urself
Answer:
K = [HI]² / [H₂] [I₂]
Explanation:
To write the expression of equilibrium constant, K, it is important that we know how to obtain the equilibrium constant.
The equilibrium constant, K for a given reaction is simply defined as the ratio of the concentration of the products raised to their coefficient to the concentration of the reactants raised to their coefficient. Thus, the equilibrium constant is written as follow:
K = [Product] / [Reactant]
Now, we shall determine the equilibrium constant for the reaction given in the question above. This can be obtained as illustrated below:
H₂(g) + I₂(g) —> 2HI (g)
K = [HI]² / [H₂] [I₂]