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Many double-displacement reactions are enzyme-catalyzed via the "ping pong" mechanism, so called because the reactants appear to

zhenek [66]

Answer:

D. It will decrease by a factor of 4

Explanation:

According to the question , the equation follows :

$A+B\rightarrow C+D$

Rate law : This states the rate of reaction is directly proportional to concentration of reactants with each reactant raised to some power which may or may not be equal to the stoichiometeric coefficient.

$Rate\ \alpha [A]^{a}[B]^{b}$

$r=[A]^{a}[B]^{b}$ .................(1)

STEP": First, find out the power "a" and "b"

a+b = 3 (because it is given that the reaction follow 3rd order-kinetics)

According to question, doubling the concentration of the first reactant causes the rate to increase by a factor of 2 means,

r' = 2r if [A'] = 2[A]

Here [B] is uneffected means [B']=[B]

hence new rate =

$r'=[A']^{a}[B']^{b}$

Put the value of [A'] , [B'] and r' in the above equation:

$2r=[2A]^{a}[B]^{b}$ ...........(2)

Divide equation (1) by (2) we , get

$\frac{2r}{r}=\frac{[2A]^{2}[B]^{b}}{[A]^{a}[B]^{b}}$

$2= 2(\frac{A}{A})^{a}\times (\frac{B}{B})^{b}$

Here A and A cancel each other

B and B cancel each other

We get,

$2= 2^{a}\times 1^{b}$

1^b = 1 ( power of 1 = 1)

$2= 2^{a}$

This is possible only when a = 1

We know that : a + b = 3

1 + b = 3

b =3 -1 = 2

b = 2

Hence the rate law becomes :

$r=[A]^{a}[B]^{b}$

$r=[A]^{1}[B]^{2}$ .............(3)

Look in the question now, it is asked to calculate the concentration of [B],if cut in half

Hence

[B']=1/2[B]

Insert the value of [B'] in equation (3)

$r'=[A]^{1}[B']^{2}$

$r'=[A]^{1}(\frac{1}{2}[B])^{2}$

$r'=\frac{1}{4}[A]^{1}[B]^{2}$ ............(a)

But

$r=[A]^{a}[B]^{b}$ ..............(b)

Compare equation (a) and (b) , we get

new rate r' =

r' = 1/4 r

7 0

3 years ago

URGENT PLEASE HELP

Mariulka [41]

The trend will be such that the time taken for the cross to disappear will be increasing.

<h3>Rate of reactions</h3>

The rate of reactions is affected by the concentration of reactants. The more concentrated the reactants are, the more the rate of the reaction, and vice versa. This is based on the condition that all other factors are kept constant.

In the illustrated reaction, the volume of sodium thiosulfate decreases downward while the volume of water increases. This means that the sodium thiosulfate gets more diluted as we move downward.

Thus, the reaction rate will keep decreasing. In other words, more time would be needed for the cross to disappear as the concentration of sodium thiosulfate decreases.

More on concentration and rate of reactions can be found here: brainly.com/question/13764840

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5 0

2 years ago

Sodium chloride will dissolve in water and the resulting solution will conduct electricity. 1. false 2. true

ExtremeBDS [4]

Answer:
True: Sodium Chloride Solution will conduct Electricity.

Explanation:
When Sodium Chloride is in solid form it fails to conduct current, But when it is dissolved in water it dissociates to produce a Na⁺ and Cl⁻ ions which are current conducting between two electrodes.

NaCl ₍s₎ + H₂O → Na⁺ ₍aq₎ + Cl⁻₍aq₎

3 0

3 years ago

A chemical reaction that absorbs energy in the form of heat is described as

adell [148]

endothermic is the answer

8 0

3 years ago

Read 2 more answers

You have learned how to take steps that are exactly 1m long. You take 12 steps north, then 15 steps north, 35 steps south, 11 st

ivanzaharov [21]

Answer:

you have walked 69 steps but your current location is -13

8 0

3 years ago