What are the answers according to Henry's classification.

How can citizen -scientists help with the prediction of future earthquakes

iVinArrow [24]

Answer:

Avoid downed power lines and stay away from buildings and bridges from which heavy objects might fall during an aftershock. Stay away until local officials tell you it is safe. A tsunami is a series of waves that may continue for hours. Do not assume that after one wave the danger is over.

3 0

3 years ago

Where do you think the government should put the greatest support: solar energy, wind energy, clean coal, oil exploration, gas e

True [87]

The government should put it support in a combination of sources, as no source in the present can fully provide all energy requirements.

7 0

3 years ago

Read 2 more answers

A 50.0 kg crate is pulled 375 N of force applied to a rope. The crate slides without friction.

LUCKY_DIMON [66]

Hi there!

We can use the work-energy theorem to solve.

Recall that:

$\large\boxed{W = \Delta KE = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2}$

The initial kinetic energy is 0 J because the crate begins from rest, so we can plug in the given values for mass and final velocity:

$W = \frac{1}{2}(50)(5.61^2) = 786.8025 J$

Now, we can define work:

$\large\boxed{W = Fdcos\theta}}$

Now, plug in the values:

$786.8025 = Fdcos\theta\\\\786.8025 = (375)(3.07)cos\theta$

Solve for theta:

$cos\theta = .6834\\\theta = cos^{-1}(.6834) = \boxed{46.887^o}$

4 0

2 years ago

A runner traveling with an initial velocity of 1.1 m/s accelerates at a constant rate of 0.8 m/s2fora time of 2.0 s.(a).What is

pychu [463]

Answer:

The final velocity of the runner at the end of the given time is 2.7 m/s.

Explanation:

Given;

initial velocity of the runner, u = 1.1 m/s

constant acceleration, a = 0.8 m/s²

time of motion, t = 2.0 s

The velocity of the runner at the end of the given time is calculate as;

$v = u + at$

where;

v is the final velocity of the runner at the end of the given time;

v = 1.1 + (0.8)(2)

v = 2.7 m/s

Therefore, the final velocity of the runner at the end of the given time is 2.7 m/s.

7 0

2 years ago

The volume of gas in a flexible container at a depth of 10 m/33 ft will expand to ______ its original volume if taken to the sur

natulia [17]

The volume of gas in a flexible container at a depth of 10 m/33 ft will expand to double its original volume if taken to the surface.

What is volume:

The amount of space that a substance or object occupies.

Volume is denoted with letter V

What is a gas molecule?

Generally, a gas molecule is simply defined as a combination of numbers of atoms that are connected one to another.

here, 10 m/33 feet of sea water is taken to exerts a gauge pressure that is the same pressure as the atmosphere.

This means that we add one atmosphere/bar pressure for every 10 m/33 feet you descend.

The effect of this is that,

at 10 m/33 ft absolute pressure is two ata/bar

Adding another 10 m/33 ft to this depth to make it 20 m/66 ft, puts you under under three ata/bar of pressure and so on.

Descending to a depth it means that you have double the ata/bar pressure acting on you. If you decide to resurface, the pressure on the flexible container will reduce by a factor of two.

Since volume is inversely proportional to the pressure,

If the pressure reduces by a factor of 2, then the volume will increase by a factor of two.

Learn more about volume of gas here:

<u>brainly.com/question/17328636</u>

#SPJ4

3 0

1 year ago