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Lemur [1.5K]
3 years ago
13

The ratio of 14C to 12C in living organisms is 1.3 × 10-12. The fossilized remains of an organism are discovered and the ratio o

f 14C to 12C in the fossil is measured to be 4.6 × 10-13. How long ago, in years was the organism alive? (The half life of 14C is 5,730 years.)
Mathematics
1 answer:
soldi70 [24.7K]3 years ago
8 0

Answer:

t = 8588 years

Step-by-step explanation:

From the given information:

Using the formula:

k = \dfrac{In (2)}{t_{1/2}}

Given that:

t_{1/2} = 5730 years

Then:

k = \dfrac{In (2)}{5730}

k = \dfrac{0.6931472}{5730}

k = 1.20968 × 10⁻⁴

However; the expression to find the value of x is:

x= x_oe^{-kt}

4.6 \times 10^{-13} = 1.3 \times 10^{-12} \times e^{(-1.20968\times 10^{-4} \times t)}

\dfrac{4.6 \times 10^{-13} }{1.3 \times 10^{-12}}=  e^{(-1.20968\times 10^{-4} \times t)}

0.353846=  e^{(-1.20968\times 10^{-4} \times t)}

(-1.20968 × 10⁻⁴ × t) = In(0.353846)

(-1.20968 × 10⁻⁴ × t) = -1.03889

t = \dfrac{-1.03889}{-1.20968 \times 10^{-4}}

t = 8588 years

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