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lara [203]
3 years ago
12

The nucleus is surrounded by a semipermeable membrane. What would happen if this layer were permeable to most substances?

Biology
2 answers:
AlexFokin [52]3 years ago
8 0

Large molecules would be able to enter and damage the nucleus (apex)

malfutka [58]3 years ago
5 0
The nucleus would become damaged
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Why might there be more dissolved oxygen in a lake in Vermont than in a similar sized lake in Florida in summer?
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What are some of the challenges to treating exotic animals
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Read 2 more answers
In certain mice, long tails (T) are dominant over short tails (t). If 2 hybrid mice mate, what will the outcome be?
yuradex [85]

Answer:

3 long tails : 1 short tail

Explanation:

This question involves a single gene coding for tail length in mice. The allele for long tail (T) is dominant over the allele for short tail (t). This means that an heterozygous mice will possess the long tail length.

According to this question, in a cross between two hybrid or heterozygote mice i.e. Tt × Tt, the following gametes will be produced by each parent:

Tt - T and t

Using these gametes in a punnet square (see attached image), the following will be produced: TT, Tt, Tt and tt.

Offsprings with genotype TT, Tt and Tt will have a LONG TAIL while genotype  tt will have a SHORT TAIL. Hence, the phenotypic ratio will be 3 long tails : 1 short tail.

7 0
3 years ago
The cross-fertilization of two different, but true-breeding, varieties of pea plants will _____.
Tresset [83]

Answer: Result in Hybrid Plants

Explanation:

The cross-fertilization of two different, but true-breeding, varieties of pea plants will <u>result in hybrid plants</u>.

3 0
3 years ago
A fruit fly of genotype B R/b r is testcrossed with b r/b r. In 84 percent of the meioses, there are no chiasmata between the li
Citrus2011 [14]

Answer:

4 percent (4%)

Explanation:

A single crossover occurs between two (non-sister) chromatids belonging to homologous chromosomes. In this case, 16 percent of the meioses have a single crossover, thereby it will produce 8 percent of the chromosomes with the original (parental) combination in the progeny and the remaining 8 percent should be recombinants. From this result, it is reasonable to conclude that half of these recombinants should be 'Br' (and the other remaining 4 percent should be recombinants 'bR'), and therefore the answer is 4 percent (4%).

5 0
2 years ago
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