Answer:
x^2 -6x + 222/25
Step-by-step explanation:
If the zeros are as above, then ;
x = 3-√3/5 or x = 3 + √3/5
Firstly, let’s represent √3/5 by b
Thus;
The two roots are ;
x = 3-b or x = 3 + b
so;
x+ b -3 and x -3-b
The quadratic equation is the product of the two
(x + b-3)(x - b -3)
x(x - b-3) + b(x -b -3) -3(x - b -3)
= x^2 -bx -3x + bx -b^2 -3b -3x + 3b + 9
Collect like terms and we are left with;
x^2 -6x -b^2 + 9
So let’s put back b = √3/5
x^2 -6x -(√3/5)^2 + 9
x^2 -6x -3/25 + 9
x^2 -6x + 222/25
Answer:
-12
Step-by-step explanation:
-6 - -4*-3/-2
-6 - 12/-2
-6-6
-12
Answer:
55,000
Step-by-step explanation:
I already explained it on another problem but I'll show the equation again.
0.74x = 40,700
x = 55,000
Step-by-step explanation:
We want to find two things-- the speed of the boat in still water and the speed of the current. Each of these things will be represented by a different variable:
B = speed of the boat in still water
C = speed of the current
Since we have two variables, we will need to find a system of two equations to solve.
How do we find the two equations we need?
Rate problems are based on the relationship Distance = (Rate)(Time).
Fill in the chart with your data (chart attached)
The resulting speed of the boat (traveling upstream) is B-C miles per hour. On the other hand, if the boat is traveling downstream, the current will be pushing the boat faster, and the boat's speed will increase by C miles per hour. The resulting speed of the boat (traveling downstream) is B+C miles per hour. Put this info in the second column in the chart. Now plug it into a formula! <u>Distance=(Rate)(Time) </u>Now solve using the systems of equations!
Answer:
The solution of a system of linear equations is:
D. The values of the variables that satisfy both equations.