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jek_recluse [69]
3 years ago
6

Sorry im not smart. will give brainliest

Mathematics
2 answers:
MakcuM [25]3 years ago
8 0

Answer:

The answer is 161051

..........

musickatia [10]3 years ago
3 0

Answer:

161,051

Step-by-step explanation:

\frac{(16-5)^{7} }{(3+8)^{2} }\\

First solve the parenthesis

\frac{11^{7} }{11^{2} }

Then multiply by the exponents (Multiply the numerator by itself 7 times, the denominator by itself 2 times)

\frac{19,487,171}{121}

Divide the numerator by the denominator to get your answer of:

161,051

You might be interested in
Please help with number 11 please.
Tomtit [17]

Answer: 4/10

Step-by-step explanation:

2/5 = ?/10 As the amount of pieces correspond to the denominator

As 5x2 = 10

2x2 = 4

5 0
2 years ago
4.5 - d > 2.5 substitute 2.5 for d
den301095 [7]

Answer:

so whats the question?

Step-by-step explanation:

5 0
2 years ago
Two sides of a triangle are equal in length and double the length of the shortest side. The perimeter of the triangle is 36 inch
chubhunter [2.5K]

Answer:

Two equal sides = 14.4 inches each

Shortest side = 7.2 inches

Step-by-step explanation:

a + b + c = 36

a = b

a = 2c

then:

c = a/2

a + a + a/2 = 36

2a + a/2 = 36

4a/2 + a/2 = 36

5a/2 = 36

a = 2*36/5

a = 72/5

a = 14.4

a = 2c

14.4 = 2*c

c = 14.4/2

c = 7.2

a = b

b = 14.4

Check:

14.4 + 14.4 + 7.2 = 36

3 0
3 years ago
Please need help with this question m
katovenus [111]

Answer:

D.

Step-by-step explanation:

3(5)+2 > 14= 17>14 which is true

10-5 less than or equal to 7

true, 5 is less than 7

7 0
3 years ago
Read 2 more answers
(1CQ) Determine whether the series -8/5+32/25-128/125+... is convergent or divergent.
Ivan

Answer:

The series is convergent answer ⇒ (a)

Step-by-step explanation:

* The series is -8/5 + 32/25 + -128/125 + ........

- It is a geometric series with:

- first term a = -8/5 and common ratio r = 32/25 ÷ -8/5 = -4/5

* The difference between the convergent and divergent

  in the geometric series is :

- If the geometric series is given by  sum  = a + a r + a r² + a r³ + ...

* Where a is the first term and r is the common ratio

* If |r| < 1 then the following geometric series converges to a / (1 - r).  

- Where a/1 - r is the sum to infinity

* The proof is:

∵ S = a(1 - r^n)/(1 - r) ⇒ when IrI < 1 and n very large number

∴ r^n approach to zero

∴ S = a(1 - 0)/(1 - r) = a/(1 - r)

∴ S∞ = a/1 - r

* If |r| ≥ 1 then the above geometric series diverges

∵ r = -4/5

∴ IrI = 4/5

∴ IrI < 1

∴ The series is convergent

3 0
3 years ago
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