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oksano4ka [1.4K]
3 years ago
5

What is 2/10ths written as a decimal

Mathematics
1 answer:
ehidna [41]3 years ago
7 0
Hey there! :D

2/10s= .2

The place after the decimal is the tenth so place. That fraction represents “two tenths”.

I hope this helps!
~kaikers
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14. A satellite orbits 22, 300 miles above the equator. It completes one revolution in 24 hours. Assume that the radius of the E
quester [9]

Answer:

Displacement = 0 mi

Distance = 164,996.45 mi

Step-by-step explanation:

In this case, the displacement will be zero because the satellite goes back to its starting point after one day. If there is no distance traveled between the starting point and the ending point, then the Displacement will be zero.

When it comes to the distance, we will need to calculate the perimeter of the circle the satellite describes when making one whole turn around the earth.

The perimeter of a circle is given by the equation:

p=2\pi r

so we need to start by finding what the radius of the circle is. This radius if found by adding the radius of the earth and the distance above the equation the satellite is located at, so we get that:

r=r_{earth}+h

where h is the height of the satellite, so the radius of the circle is:

r=22,300mi + 3,960 mi

so

r=26,260 mi

so now we can use the perimeter equation to get:

p=2\pi r

p=2\pi (26,260)

So the distance traveled by the satellite in one day will be:

P=164,996.45 mi.

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3 years ago
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mrs_skeptik [129]
What is the answer you want to get?
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3 years ago
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Answer:

The forth box for c will be 22

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A garbage container is to be constructed out of 400 ft2 of material. The vessel will have a square base and an open top. Find th
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Answer:

  11.547 ft wide by 5.774 ft high

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Step-by-step explanation:

Volume is maximized for a given area by having the area of a pair of opposite sides equal the area of the bottom. That means the overall area of the container is 3 times the area of the bottom. Then the square bottom will have a width of ...

  w = √(400/3) ≈ 11.547 . . . feet

The height is half that, so is ...

  h = w/2 = 11.547/2 ≈ 5.774 . . . feet

The capacity is then ...

  w²h = (11.547 ft)²(5.774 ft) = 769.800 ft³

The container is 11.547 ft wide by 5.774 ft high. It has a capacity of 769.800 cubic feet.

_____

You want to maximize w^2h subject to w^2 + 4wh = 400. Solving the constraint equation for h, we get h = (400 -w^2)/(4w) and the volume we want to maximize can be written as ...

  V = w(400-w^2)/4

This will be an extreme when dV/dw = 0, so we want to solve ...

  dV/dw = 0 = 100 -(3/4)w^2

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