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3 years ago

Identify the radius of the circle whose equation is (x - 2)^2 + (y - 8)^2 = 16.

Mathematics

2 answers:

KiRa [710]3 years ago

5 0

The radius is 4
the equation of a circle is (x-h)^2+(y-k)^2=r^2
in this case, 16=r^2
so r=4

Misha Larkins [42]3 years ago

3 0

16^2 is the radius, so 16 squared is 4. Therefore the radius is equal to 4

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Which shows the following expression after the negative exponents have been eliminated?

belka [17]

Answer:

The given expression $\frac{a^3}{ab^{-4}}$ after the negative exponents have been eliminated becomes $\frac{a^3b^{4}}{ab^{2}}$

Step-by-step explanation:

Given expression $\frac{a^3b^{-2}}{ab^{-4}}$

We have to write expression after the negative exponents have been eliminated and a ≠ 0 and b ≠ 0.

Consider the given expression $\frac{a^3b^{-2}}{ab^{-4}}$

We have to eliminate the negative exponents,

Using property of exponents, $x^{-m}=\frac{1}{x^m}$ we have ,

$b^{-2}=\frac{1}{b^2} \\\\b^{-4}=\frac{1}{b^4}$

Substitute, we get,

$\frac{a^3}{ab^{-4}}$ becomes $\frac{a^3b^{4}}{ab^{2}}$

Thus, the given expression $\frac{a^3}{ab^{-4}}$ after the negative exponents have been eliminated becomes $\frac{a^3b^{4}}{ab^{2}}$

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3 years ago

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tia_tia [17]

Answer:

x=4 y=1

Step-by-step explanation:

given equation

x+y=5

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and

x-2y=2

so x= 2+2y........(ii)

then

5-y=2+2y

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3 years ago

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.....................................

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2 years ago

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3 years ago

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