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sergey [27]
2 years ago
12

Tracy works at North College as a math teacher. She will be paid $900 for each credit hour she teaches. During the course of her

first year of teaching, she would teach a total of 50 credit hours. The college expects her to work a minimum of 170 days (and less and her salary would be reduced) and 8 hours each day.
What is her gross monthly income?

Group of answer choices

$75

$900

$3,750

$45,000

Mathematics
1 answer:
AlladinOne [14]2 years ago
5 0

THE CORRECT ANSWER WAS

$3,750

<em>*100% CORRECT ANSWERS </em>

<em>(SEE ATTACHMENTS)</em>

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Is (-2, 6) a solution to this system of equations?
nasty-shy [4]
I think the answer is no. I’m not sure. I’m sorry if incorrect
8 0
2 years ago
Q.6. The equation of the ellipse whose centre is at the origin and the x-axis, the major axis, which passes
azamat

<h3>Answer:</h3>

Equation of the ellipse = 3x² + 5y² = 32

<h3>Step-by-step explanation:</h3>

<h2>Given:</h2>

  • The centre of the ellipse is at the origin and the X axis is the major axis

  • It passes through the points (-3, 1) and (2, -2)

<h2>To Find:</h2>

  • The equation of the ellipse

<h2>Solution:</h2>

The equation of an ellipse is given by,

\sf \dfrac{x^2}{a^2} +\dfrac{y^2}{b^2} =1

Given that the ellipse passes through the point (-3, 1)

Hence,

\sf \dfrac{(-3)^2}{a^2} +\dfrac{1^2}{b^2} =1

Cross multiplying we get,

  • 9b² + a² = 1 ²× a²b²
  • a²b² = 9b² + a²

Multiply by 4 on both sides,

  • 4a²b² = 36b² + 4a²------(1)

Also by given the ellipse passes through the point (2, -2)

Substituting this,

\sf \dfrac{2^2}{a^2} +\dfrac{(-2)^2}{b^2} =1

Cross multiply,

  • 4b² + 4a² = 1 × a²b²
  • a²b² = 4b² + 4a²-------(2)

Subtracting equations 2 and 1,

  • 3a²b² = 32b²
  • 3a² = 32
  • a² = 32/3----(3)

Substituting in 2,

  • 32/3 × b² = 4b² + 4 × 32/3
  • 32/3 b² = 4b² + 128/3
  • 32/3 b² = (12b² + 128)/3
  • 32b² = 12b² + 128
  • 20b² = 128
  • b² = 128/20 = 32/5

Substituting the values in the equation for ellipse,

\sf \dfrac{x^2}{32/3} +\dfrac{y^2}{32/5} =1

\sf \dfrac{3x^2}{32} +\dfrac{5y^2}{32} =1

Multiplying whole equation by 32 we get,

3x² + 5y² = 32

<h3>Hence equation of the ellipse is 3x² + 5y² = 32</h3>
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Step-by-step explanation:

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Step-by-step explanation:

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If f(x)= 3 over x+2- square root x-3 f(19)=
PSYCHO15rus [73]
F(19)= (3/(19+2)) - sqrt(19-3)
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3 years ago
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