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aleksandrvk [35]
3 years ago
14

Simplify the following: 9(v-4)

Mathematics
1 answer:
alexdok [17]3 years ago
4 0
You use the distributive property.

9 times v = 9v
9 times -4 = -36

Therefore the answer is
9v-36

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I need helpppppp i have no idea what im looking at lol
Fed [463]

The correct answer is option B which is  Cot\theta=\dfrac{24}{7}.

<h3>What is trigonometry?</h3>

Trigonometry is the branch of mathematics which set up a relationship between the sides and angle of the right-angle triangles.

Given that:-

Sec\theta=\dfrac{25}{24}

The value of cot theta will be calculated as:-

We know that sec theta is the ratio of hypotenuse and base and cot theta is the ratio of base and perpendicular so we will find the value of perpendicular by applying the Pythagorean theorem.

H² = P²  +  B²
P² = H²  -  B²

P²  =  25²  -  24 ²  = 49

P  = √49 =  7

Now the value of cot theta will be calculated as:-

Cot\theta =\dfrac{B}{P}=\dfrac{24}{7}

Therefore the correct answer is option B which is  Cot\theta=\dfrac{24}{7}.

To know more about Trigonometry follow

brainly.com/question/24349828

#SPJ1

5 0
2 years ago
Mrs. Hilt bought 15 books. Sh paid $11 for each book. She later sold all 15 books for $25 each. What is the difference between t
sweet [91]
Total amount of money paid
=11 x 15
=$165

total amount of money sold
=25 x 15
=$375

difference
= 375 - 165
=$210
4 0
3 years ago
Which number is IRRATIONAL?
Irina18 [472]

Answer:

√27

Step-by-step explanation:

√9, √36, and √81 are rational

4 0
3 years ago
The crime rate of a certain city is increasing by exactly 6% each year. If there were 550
kap26 [50]

Using an exponential function, it is found that the approximate number of crimes in the year of 2016 was of 2502.

<h3>What is an exponential function?</h3>

An increasing exponential function is modeled by:

A(t) = A(0)(1 + r)^t

In which:

  • A(0) is the initial value.
  • r is the growth rate, as a decimal.

In this problem, there were 550 crimes in the initial year observed, and the growth rate is of 6%, hence the parameters are A(0) = 550, r = 0.06, and the equation is given by:

A(t) = A(0)(1 + r)^t

A(t) = 550(1 + 0.06)^t

A(t) = 550(1.06)^t

2016 is 26 years after 1990, hence:

A(26) = 550(1.06)^{26} \approx 2502

The approximate number of crimes in the year of 2016 was of 2502.

More can be learned about exponential functions at brainly.com/question/25537936

8 0
2 years ago
evaluate the fermi function for an energy KT above the fermi energy. find the temperature at which there is a 1% probability tha
dybincka [34]

Complete Question

Evaluate the Fermi function for an energy kT above the Fermi energy. Find the temperature at which there is a 1% probability that a state, with an energy 0.5 eV above the Fermi energy, will be occupied by an electron.

Answer:

a

The Fermi function for the energy KT is  F(E_o) =  0.2689

b

The temperature is  T_k  =  1261 \  K

Step-by-step explanation:

From the question we are told that

   The energy considered is  E = 0.5 eV

Generally the Fermi  function is mathematically represented as

       F(E_o) =  \frac{1}{e^{\frac{[E_o - E_F]}{KT} } + 1 }

    Here K is the Boltzmann constant with value k = 1.380649 *10^{-23} J/K

            E_F  is the Fermi energy

            E_o  is the initial energy level which is mathematically represented as

     E_o = E_F + KT

So

     F(E_o) =  \frac{1}{e^{\frac{[[E_F + KT] - E_F]}{KT} } + 1}

=>   F(E_o) =  \frac{1}{e^{\frac{KT}{KT} } + 1}

=>   F(E_o) =  \frac{1}{e^{ 1 } + 1}

=>   F(E_o) =  0.2689

Generally the probability that a state, with an energy 0.5 eV above the Fermi energy, will be occupied by an electron is mathematically represented by the  Fermi  function as

     F(E_k) =  \frac{1}{e^{\frac{[E_k - E_F]}{KT_k} } + 1 }  = 0.01

HereE_k is that energy level that is  0.5 ev above the Fermi energy  E_k = 0.5 eV  + E_F

=>   F(E_k) =  \frac{1}{e^{\frac{[[0.50 eV + E_F] - E_F]}{KT_k} } + 1 }  = 0.01

=>   \frac{1}{e^{\frac{0.50 eV ]}{KT_k} } + 1 }  = 0.01

=>   1 = 0.01 * e^{\frac{0.50 eV ]}{KT_k} } + 0.01

=>   0.99 = 0.01 * e^{\frac{0.50 eV ]}{KT_k} }

=>   e^{\frac{0.50 eV ]}{KT_k} }  = 99

Taking natural  log of both sides

=>   \frac{0.50 eV }{KT_k} }  =4.5951

=>    0.50 eV   =4.5951 *  K *  T_k

Note eV is electron volt and the equivalence in Joule is     eV  =  1.60 *10^{-19} \  J

So

     0.50 * 1.60 *10^{-19 }   =4.5951 *  1.380649 *10^{-23} *  T_k

=>   T_k  =  1261 \  K

7 0
3 years ago
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