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Tema [17]
3 years ago
6

2. Which fraction is in its simplest form? 2/4 2/8 2/6 2/5

Mathematics
2 answers:
wariber [46]3 years ago
7 0

Answer:

2/5

Step-by-step explanation:

2 / 4 could be divided by two in both sides.

2 ÷ 2 = 1

4 ÷ 2 = 2

2/4 = 1/2

Same goes for 2/8 and 2/6

2 ÷ 2 = 1

8 ÷ 2 = 4

2/8 = 1/4

2 ÷ 2 = 1

6 ÷ 2 = 3

2/6 = 1/3

2/5 however, could not be divided by two on both sides because there is 5 and it is not a factor of 2. So it is in its simplest form

CaHeK987 [17]3 years ago
4 0

Answer: 2/5

Step-by-step explanation: 2/5 cannot be simplified any further because there is no number that will go into both of them equally. 2/4, 2/8, and 2/6 all have even numerators and denominators, so they are all divisible by 2. 2 only goes into the numerator in the fraction 2/5, thus, it is in its simplest form.

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Find the range of the function<br> F(x) = (x-2)2 +2
viktelen [127]
(x - 2)^2 will always be positive and will have a minimum value of  0 

so f(x) will have minimum of 2

Range is [2,∞)
8 0
3 years ago
A piece of rope 20 feet long is cut from a longer piece that is at least 32 feet long. The remainder is cut into four pieces of
algol13

Answer:

smaller pieces must be larger than 3 feet

Step-by-step explanation:

x is the longer piece

x>32

x-20>12

12/4=3

smaller pieces resembled as y

y>3

5 0
3 years ago
Read 2 more answers
I have nooooo clue, please help
Aleksandr-060686 [28]

Answer:

case a) x^{2}=3y ----> open up

case b) x^{2}=-10y ----> open down

case c) y^{2}=-2x ----> open left

case d) y^{2}=6x ----> open right

Step-by-step explanation:

we know that

1) The general equation of a vertical parabola is equal to

y=a(x-h)^{2}+k

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open upward and the vertex is a minimum

If a<0 ----> the parabola open downward and the vertex is a maximum

2) The general equation of a horizontal parabola is equal to

x=a(y-k)^{2}+h

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open to the right

If a<0 ----> the parabola open to the left

Verify each case

case a) we have

x^{2}=3y

so

y=(1/3)x^{2}

a=(1/3)

so

a>0

therefore

The parabola open up

case b) we have

x^{2}=-10y

so

y=-(1/10)x^{2}

a=-(1/10)

a

therefore

The parabola open down

case c) we have

y^{2}=-2x

so

x=-(1/2)y^{2}

a=-(1/2)

a

therefore

The parabola open to the left

case d) we have

y^{2}=6x

so

x=(1/6)y^{2}

a=(1/6)

a>0

therefore

The parabola open to the right

3 0
3 years ago
Please help me with this question
Anon25 [30]
I'm not 100% but I think its going to be a positive answer choice. 

So i would say 1/2




4 0
3 years ago
There is a fire in the third floor of a building, 22 feet above the ground. The fire truck has a 16-foot tall ladder on top, and
Over [174]

Answer: Yes the ladder will reach the fire

Step-by-step explanation: Please refer to the attached diagram for details.

The fire is at point A, while the top of the truck is at point C. The fire is actually burning at 22 feet off the ground, but because the fire truck itself is already 6 feet off the ground, the point that would serve as the base of the building would be 16 feet from the third floor (which is 22 feet minus 6 feet). Hence, point A to point B is 16 feet. So we need to calculate if line AC (from the truck to the fire at the third floor, labeled as b) shall equal the length of the ladder which is 16-foot long.

The angle of the ladder with the top of the truck is 75 degrees. Therefore,

Sin 75 = opposite/hypotenuse

Sin 75 = 16/b

By cross multiplication we now have

b = 16/Sin 75

b = 16/0.9659

b = 16.56

If the distance from A to C is 16.56 feet, then the 16-foot long ladder would reach the fire.

8 0
3 years ago
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