<span>Probability = 0.063
Fourth try = 0.0973
Let X be the number of failed attempts at passing the test before the student passes. This
is a negative binomial or geometric variable with x â {0, 1, 2, 3, . . .}, p = P(success) = 0.7
and the number of successes to to observe r = 1. Thus the pmf is nb(x; 1, p) = (1 â’ p)
xp.
The probability P that the student passes on the third try means that there were x = 2
failed attempts or P = nb(2, ; 1, .7) = (.3)2
(.7) = 0.063 . The probability that the student
passes before the third try is that there were two or fewer failed attmpts, so P = P(X ≤
2) = nb(0, ; 1, .7) + nb(1, ; 1, .7) + nb(2, ; 1, .7) = (.3)0
(.7) + (.3)1
(.7) + (.3)2
(.7) = 0.973 .</span>
The answer should be 11/84
Answer:
Answered
Step-by-step explanation:
Length is stored in variable named length
the width in one named width
the expression for the diagonal of the rectangle can be written as
double diagonal = Math.sqrt(Math.pow(length,2) + Math.pow(width,2))
Simple math. 350 - 90 = 260. So Hector needs to drive 260 km more to reach his cousin
