Answer: propanal and propanoic acid
Explanation: first of all Oxidation of alcohol with mild oxidizing reagent PCC gives Carbonyl compounds and with strong oxidizing agent like CrO3 and kmno4 gives carboxylic acids.
And primary alcohol gives Aldehyde with mild oxidizing reagent and carboxylic acids with strong oxidizing agent.
And ketone is formed with secondary alcohol by both mild and strong Oxidizing agent.
Here our compound is primary alcohol hence we will get propanal and propanoic acid depending on type of Oxidizing agent
Answer:
The standard enthalpy of formation of NOCl(g) at 25 ºC is 105 kJ/mol
Explanation:
The ∆H (heat of reaction) of the combustion reaction is the heat that accompanies the entire reaction. For its calculation you must make the total sum of all the heats of the products and of the reagents affected by their stoichiometric coefficient (number of molecules of each compound that participates in the reaction) and finally subtract them:
Enthalpy of the reaction= ΔH = ∑Hproducts - ∑Hreactants
In this case, you have: 2 NOCl(g) → 2 NO(g) + Cl₂(g)
So, ΔH=
Knowing:
- ΔH= 75.5 kJ/mol
- = 90.25 kJ/mol
- = 0 (For the formation of one mole of a pure element the heat of formation is 0, in this caseyou have as a pure compound the chlorine Cl₂)
- =?
Replacing:
75.5 kJ/mol=2* 90.25 kJ/mol + 0 -
Solving
-=75.5 kJ/mol - 2*90.25 kJ/mol
-=-105 kJ/mol
=105 kJ/mol
<u><em>The standard enthalpy of formation of NOCl(g) at 25 ºC is 105 kJ/mol</em></u>
Answer:
Yes
Explanation:
Neither Calcium nor hydrogen nor oxygen are alkali metals
- Alkali metals are Group 1 elements
- They are very soft and mellable.
- H,Li,Na,K,Cs,Fr are included in it however H is not a actual member
Here
Ca(OH)_2 is the compound
Vant Hoff factor is 3
As it's greater than 1 it's a very strong base .
The pOH of this comes around 1.5 to 1.3
So very heavy ionic dissociation
Strong Alkali
Answer: The answer is true.
Explanation: Avogadro's number is a mole, which concludes that this statement is true.
Answer:
The correct answer is 6.265 M.
Explanation:
To find the molarity of the solution, we first must recall that molarity represents the number of moles of solute divided by the number of liters of solution. Thus, our first step should be to convert the solute amount in grams to moles, using the given molar mass.
266.07 g * (1 mol/169.88 g) = 1.5662 mol
Now, we can find the molarity using the following formula:
Molarity = moles solute/liters solution
M = 1.5662 mol/0.25 L
M = 6.265 M
Therefore, the molarity of the solution is 6.265 M.
Hope this helps!