A. The wavelength of light that is emitted is 122 nm.
<h3>
What is wavelength?</h3>
Wavelength is the distance between identical points (adjacent crests) in the adjacent cycles of a waveform signal propagated in space or along a wire.
<h3>Wavelength of light is emitted</h3>
When an electron falls from the n = 2 to the n = 1 energy levels in a Hydrogen atom, the wavelength of light is emitted is calculated as follows;
¹/λ = R(1/n₁² - 1/n₂²)
¹/λ = 109677(1/1 - 1/2²)
¹/λ = 109677(1 - ¹/₄)
¹/λ = 82,257.25
λ = 1/8,225.25
λ = 1.22 x 10⁻⁵ cm
λ = 1.22 x 10⁻⁷ m
λ = 122 nm
Thus, the wavelength of light that is emitted is 122 nm.
Learn more about wavelength here: brainly.com/question/10728818
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Weathering because Weathering<span> is the process where </span>rock<span> is dissolved, worn away or </span>broken down into smaller<span> and </span>smaller<span> pieces. There are </span>mechanical<span>, chemical and organic </span>weathering<span>processes. Organic </span>weathering<span> happens when plants </span>break<span> up </span>rocks<span> with their growing roots or plant acids help dissolve </span>rock<span>.</span>
C. It increases and the pH stays constant.
Answer:
2.09 atm
Explanation:
We can solve this problem by using the equation of state for an ideal gas, which relates the pressure, the volume and the temperature of an ideal gas:
where
p is the pressure of the gas
V is its volume
n is the number of moles
R is the gas constant
T is the absolute temperature
In this problem we have:
n = 0.65 mol is the number of moles of the gas
V = 8.0 L is the final volume of the gas
is the temperature of the gas
is the gas constant
Solving for p, we find the final pressure of the gas:
Your first step should be to analyse the compound. For example, if the compound is carbon, you know it always has a valence of four, so, if it has a formula C2H4 (ethylene) it obviously has a double bond. There are difficulties here because benzene C6H6 can be considered to have 6 1.5 C-C bonds, being aromatic.
A second step is to look at its structure. Double bonds are traditionally shorter than single bonds; triple bonds shorter still. Covalent bonds do have typical lengths, nevertheless you can still have problems.
<span>A third step is to consider reactivity. For example, if you have a C=C double bond, you can add, say, bromine to it Thus C2H4 gives C2H4Br2, and by adding two bromine atoms you know you have one double bond. Again, benzene becomes an awkward molecule, but because of this, you know benzene does not have double bonds in the traditional sense</span>
