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bulgar [2K]
3 years ago
15

Can some one help me with this soon as possible please will give brainliest

Chemistry
1 answer:
lana66690 [7]3 years ago
7 0

1. C

2. C

3. In elastic deformation, the deformed body returns to its original shape and size after the stresses are gone. In ductile deformation, there is a permanent change in the shape and size but no fracturing occurs. In brittle deformation, the body fractures after the strength is above the limit. 

4. Normal faults are faults where the hanging wall moves in a downward force based on the footwall; they are formed from tensional stresses and the stretching of the crust. Reverse faults are the opposite and the hanging wall moves in an upward force based on the footwall; they are formed by compressional stresses and the contraction of the crust.  Thrust faults are low-angle reverse faults where the hanging wall moves in an upward force based on the footwall; they are formed in the same way as reverse faults. Last, Strike-slip faults are faults where the movement is parallel to the crust of the fault; they are caused by an immense shear stress. 


I hope this helped :D

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What is the silver ion concentration in a solution prepared by mixing 369 mL 0.373 M silver nitrate with 411 mL 0.401 M sodium c
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Answer:

[A g + ]  =  3.12 *10^-6 M

Explanation:

Step 1: Data given

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Volume sodium chromate = 411 mL

Molarity sodium chromate = 0.401 M

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Step 2: The balanced equation

2 A g + ( a q )  +  C rO4^2-  ( a q )  →Ag2CrO4 (  s)

Step 3:

[Ag+]i = [AgNO3] * V1/(V1+V2) * 1 mol Ag+ / 1 mol AgNO3

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[Ag+]i = 0.176 M

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[C rO4^2i = 0.401 M * 0.411 / (0.369+0.411)

[C rO4^2]i = 0.211 M

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1.2 * 10^− 12  = ( 2 x ) ²* 0.123M

x = 1.56 * 10^-6

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4 0
3 years ago
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4 0
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Explanation:

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