Explanation:
Relation between entropy change and specific heat is as follows.
The given data is as follows.
mass = 500 g, 
= 24.4 J/mol K
= 500 K, 
= 250 K
Mass number of copper = 63.54 g /mol
Number of moles = 
= 
= 7.86 moles
Now, equating the entropy change for both the substances as follows.
![7.86 \times 24.4 \times [T_{f} - 250]](https://tex.z-dn.net/?f=7.86%20%5Ctimes%2024.4%20%5Ctimes%20%5BT_%7Bf%7D%20-%20250%5D)
= ![7.86 \times 24.4 \times [500 -T_{f}]](https://tex.z-dn.net/?f=7.86%20%5Ctimes%2024.4%20%5Ctimes%20%5B500%20-T_%7Bf%7D%5D)
= 750
So, 
= 
- For the metal block A, change in entropy is as follows.
= ![24.4 log [\frac{375}{500}]](https://tex.z-dn.net/?f=24.4%20log%20%5B%5Cfrac%7B375%7D%7B500%7D%5D)
= -3.04 J/ K mol
- For the block B, change in entropy is as follows.
= ![24.4 log [\frac{375}{250}]](https://tex.z-dn.net/?f=24.4%20log%20%5B%5Cfrac%7B375%7D%7B250%7D%5D)
= 4.296 J/Kmol
And, total entropy change will be as follows.
= 4.296 + (-3.04)
= 1.256 J/Kmol
Thus, we can conclude that change in entropy of block A is -3.04 J/ K mol and change in entropy of block B is 4.296 J/Kmol.
Explanation:
Valence electrons are not related in anyways to nuclear reactions.
They do not take part in nuclear reactions. Only some inner orbital electrons have the tendency of taking part in nuclear reactions.
The valence electrons are the outermost electrons in an atom.
Nuclear reactions takes place in the nucleus of an atom.
Valence electrons are exchanged and shared for chemical reactions to take place in between atoms.
We can conclude that valence electrons have no relevance in nuclear reactions
learn more:
Chemical reactions brainly.com/question/3953793
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Answer:
How many grams of K2Cr2O7, are soluble in 100 g of water at 95 ºC? Solubility Curve DRAFT. 10th - 12th grade. 3326 times. Chemistry. 63% average accuracy. 3 years ago ... When 20 grams of potassium chlorate, KClO 3, is dissolved in 100 grams of water at 80 ºC, the solution can be correctly described as: answer choices . supersaturated. saturated.
Explanation:
Answer: hope this helps
To make molar NaCl solutions of other concentrations dilute the mass of salt to 1000ml of solution as follows:
0.1M NaCl solution requires 0.1 x 58.44 g of NaCl = 5.844g.
0.5M NaCl solution requires 0.5 x 58.44 g of NaCl = 29.22g.
2M NaCl solution requires 2.0 x 58.44 g of NaCl = 116.88g.
Explanation:
