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2 years ago

You invest $1,250 in a stock. The value of the stock goes up 3.2% and you sell it. How much money did you make?

Mathematics

2 answers:

I am Lyosha [343]2 years ago

5 0

Step-by-step explanation:

100:1250

103.2:x

(103.2x1250)/100

=1290

he made additional $40

suter [353]2 years ago

4 0

Answer:

$1290

Step-by-step explanation:

1250x3.2%=40

1250+40=1290

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a cylinder has a height of 12 feet and a radius of 14 feet. what is its volume? use ≈ 3.14 and round to the nearest hundredth

Komok [63]

Answer:

V = 7385.28

Step-by-step explanation:

Formula of the volume of a cylinder: V = pi*r^2*h

Since you are told to replace pi with 3.14, now plug in the numbers that you are given into the formula...

V = (3.14)(14)^2*(12)

= 7385.28

Notes: Remember you always have to divide your radius in half if it gives you a diameter, BUT since in this question it's given, you don't have to do any extra work :)

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2 years ago

Help I need you right nowwwwwwwwwwww

earnstyle [38]

Answer:

6/8

just add the fractions together after making the bottom the same

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2 years ago

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There were 500 people at a play. the admission price was $6 for general public and $3 for students. the admission receipts were

dem82 [27]

Its 880 i think but hope yhu get it right

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3 years ago

Help me plz I need help

charle [14.2K]

Answer:

-0.48

Step-by-step explanation:

(-1.2)(0.4)

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2 years ago

Suppose that an insect population’s density, in thousands per acre, during year n, can be modeled by the recursive formula: a1 =

vlabodo [156]

Answer:

The population alternates between increasing and decreasing

Step-by-step explanation:

<u><em>The options of the question are</em></u>

A) The population density decreases each year.

B) The population density increases each year.

C) The population density remains constant.

D) The population alternates between increasing and decreasing

we have

$a_n=2.9(a_n_-_1)-0.2(a_n_-_1)^2$

$a_1=8$

Find the value of $a_2$

For n=2

$a_2=2.9(a_1)-0.2(a_1)^2$

$a_2=2.9(8)-0.2(8)^2=10.4$

Find the value of $a_3$

For n=3

$a_3=2.9(a_2)-0.2(a_2)^2$

$a_3=2.9(10.4)-0.2(10.4)^2=8.528$

For n=4

$a_4=2.9(a_3)-0.2(a_3)^2$

$a_4=2.9(8.528)-0.2(8.528)^2=10.1858$

For n=5

$a_5=2.9(a_4)-0.2(a_4)^2$

$a_5=2.9(10.1858)-0.2(10.1858)^2=8.7887$

therefore

The population alternates between increasing and decreasing

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2 years ago

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