Step-by-step explanation: look so if you have
shcool A its 8v+4b=12
and
School B: 12v+4b= 16
since both classes used 4 busses we can use elimination by subtracting the A class Equation from the b class equation to solve from v for its value Then, use either equation and the now found value for v to solve for b.
You should find part of the process to be
12v+4b-(8v+4b)=12-16 which shows the van holds only a few people even before continuing the solution.
Answer -4
Answer:

Step-by-step explanation:
Work backwards with synthetic division with remainder 0 and then solve for a:
-3 | 2 a 19 3
_________
2 | 0
-3 | 2 a 19 3
_______<u> -3</u>
2 | 0
-3 | 2 a 19 3
_______<u> -3</u>
2 1 | 0
-3 | 2 a 19 3
_____<u>-18 -3</u>
2 1 | 0
-3 | 2 a 19 3
_____<u> -18 -3</u>
2 6 1 | 0
-3 | 2 a 19 3
_____<u> -18 -3</u>
2 6 1 | 0
-3 | 2 a 19 3
____<u>-6 -18 -3</u>
2 6 1 | 0
a - 6 = 6
a = 12
Answer:
6.8 gallions i believe. im not quite sure
We can try reduction order and look for a solution
. Then

Substituting these into the ODE gives



which leaves us with an ODE linear in
:

This ODE is separable; divide both sides by the coefficient of
and separate the variables to get



Integrate both sides; on the right, substitute
so that
.

Now solve for
,



then for
,


Solve for
by integrating both sides.

Substitute
again and solve for
:


then for
,

So the second solution would be


already accounts for the second term of the solution above, so we end up with

as the second independent solution.