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3 years ago

Write down the value of the 7 in 47298 in figures

Mathematics

1 answer:

8090 [49]3 years ago

7 0

Answer:

thousands or tens thousands

Step-by-step explanation:

I believe the answer is either thousands or ten thousand

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2b. Jill and Alice each sold 40 pieces of

Diano4ka-milaya [45]

Answer:

Jill sold more apples

1 more than Alice

Step-by-step explanation:

Jill sold 40 fruits

Alice sold 40 fruits

15% of Jill's sales is APPLES, that is:

15/100 = 0.15

0.15 * 40 = 6

Jill sold 6 apples.

Now, it is given Alice sold 5 apples.

Who sold more? Of course, Jill.

By how much? 6 - 5 = 1 apple more

7 0

3 years ago

Solve the following and explain your steps. Leave your answer in base-exponent form. (3^-2*4^-5*5^0)^-3*(4^-4/3^3)*3^3 please st

Naily [24]

Answer:

$\boxed{2^{\frac{802}{27}} \cdot 3^9}$

Step-by-step explanation:

I will try to give as many details as possible.

First of all, I just would like to say:

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Texting in Latex is much more clear and depending on the question, just writing down without it may be confusing or ambiguous. Be together with Latex! （＊＾Ｕ＾）人（≧Ｖ≦＊）/

$(3^{-2} \cdot 4^{-5} \cdot 5^0)^{-3} \cdot (4^{-\frac{4}{3^3} })\cdot 3^3$

Note that

$\boxed{a^{-b} = \dfrac{1}{a^b}, a\neq 0 }$

The denominator can't be 0 because it would be undefined.

So, we can solve the expression inside both parentheses.

$\left(\dfrac{1}{3^2} \cdot \dfrac{1}{4^5} \cdot 5^0 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{3^3} } }\right)\cdot 3^3$

Also,

$\boxed{a^{0} = 1, a\neq 0 }$

$\left(\dfrac{1}{9} \cdot \dfrac{1}{1024} \cdot 1 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

Note

$\boxed{\dfrac{1}{a} \cdot \dfrac{1}{b}= \frac{1}{ab} , a, b \neq 0}$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

Note

$\boxed{\dfrac{1}{\dfrac{1}{a} } = a}$

$9216^3\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left(\dfrac{ 9216^3\cdot 27}{4^{\frac{4}{27} } }\right)$

Once

$9216=2^{10}\cdot 3^2 \implies 9216^3=2^{30}\cdot 3^6$

$\boxed{(a \cdot b)^n=a^n \cdot b^n}$

And

$4^{\frac{4}{27}} = 2^{\frac{8}{27}$

We have

$\left(\dfrac{ 2^{30} \cdot 3^6\cdot 27}{2^{\frac{8}{27} } }\right)$

Also, once

$\boxed{\dfrac{c^a}{c^b}=c^{a-b}}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27$

$30-\dfrac{8}{27} = \dfrac{30 \cdot 27}{27}-\dfrac{8}{27} =\dfrac{802}{27}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27 = 2^{\frac{802}{27}} \cdot 3^6 \cdot 3^3$

$2^{\frac{802}{27}} \cdot 3^9$

4 0

3 years ago

Billie solved the equation below by completing the square, but she got the incorrect solution. In which step did Billie first ma

Tanzania [10]

Answer:

step 2

Step-by-step explanation:

we have

$x^{2} +10x-49=0$ ---> given problem

step 1

Move the constant to the right side

$x^{2} +10x=49$

the step 1 is correct

step 2

Complete the square

$x^{2} +10x+5^2=49+5^2$

$x^{2} +10x+5^2=74$

The step 2 is not correct

step 3

Rewrite as perfect squares

$(x+5)^{2}=74$

step 4

take square root both sides

$x+5=\pm\sqrt{74}$

step 5

Find the values of x

$x=-5\pm\sqrt{74}$

$x=-5+\sqrt{74}$

$x=-5-\sqrt{74}$

5 0

3 years ago

Solve for x in the equation

Sati [7]

So 1st make it equal to zero
x^2+4x-12
(x+6)(x-2)
so
x=-6 or 2 is the correct answer

8 0

3 years ago

Read 2 more answers

Real quick what is the radius of 16 cm simplest form

KIM [24]

Answer:

8cm

Explanation:

If the 16 cm is the diameter then the radius is 8 cm

8 0

3 years ago