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3 years ago

If f(x) = 8x, which of the following is the inverse of f(x)?

1 answer:

7 0

Y=8x

To find the inverse, flip the x and y variables and then solve for y.

x=8y
x/8=8y/8
x/8=y

Final answer: f^-1(x)=x/8

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What is the domain of the function; y= (x-1)2 -2

valkas [14]

It should be 2 but i’m not positive

5 0

2 years ago

Round to the nearest tenth.

laila [671]

Answer:

8.2 units

Step-by-step explanation:

Given that the only information for our triangle are 2 sides and 1 angle, we must use the Law of Cosines to find side BC

Recall the Law of Cosines

$a^2=b^2+c^2-2bc\cdot cos(A)$

Identify angles and sides

$m\angle A=23^\circ\\a=BC=?\\b=AC=14\\c=AB=6$

Solve for side "a"

$a^2=b^2+c^2-2bc\cdot cos(A)\\\\a^2=14^2+6^2-2(14)(6)\cdot cos(23^\circ)\\\\a^2=196+36-168cos(23^\circ)\\\\a^2=222-168cos(23^\circ)\\\\a=\sqrt{222-168cos(23^\circ)}\\ \\a\approx8.2$

Therefore, the length of line segment BC is about 8.2 units

8 0

2 years ago

A plant is already 52 centimeters tall, and it will grow one centimeter every month. Let H be the plant's health (in centimeters

Tasya [4]

Plant's height after 31 months:82 centimeters

<h3>How to find the height of the plant</h3>

The equation that can be used to find the height of the plant is given as

h = 52 centimeters + 1m

We have that the plant grows at 1 centimeter every month hence we have 1m in the equation.

Then the number of periods is m, Now we are to find the height in this period of time

h = 52 + 1*31

= 51 + 31

= 82

Hence the height after 31 months is given as 82 centimeters.

Read more on height here:

brainly.com/question/73194

#SPJ1

5 0

1 year ago

What is 129 multiply by 75

lianna [129]

Answer: 9675

Step-by-step explanation: u don’t want to know do u

4 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Csqrt%7B%20x%5E%7B2%7D-10x%2B25%7D%2B25%2B12%5Csqrt%7Bx%7D%20%3D15%5Csqrt%7Bx%7D" id="TexFor

vodomira [7]

Step-by-step explanation:

$\sqrt{ x^{2}-10x+25}+25+12\sqrt{x} =15\sqrt{x} \\ \\ \therefore \: \sqrt{ x^{2}-10x+ {5}^{2} }+25 =15\sqrt{x} - 12\sqrt{x}\\ \\ \therefore \: \sqrt{( x - 5)^{2}}+25 =3\sqrt{x} \\ \\ \therefore \: x - 5+ 25 = 3 \sqrt{x} \\ \\ \therefore \: x + 20 = 3 \sqrt{x} \\ \\ squaring \: both \: sides \\ (x + 20)^{2} = ( {3 \sqrt{x} })^{2} \\ \therefore \: {x}^{2} + 40x + 400 = 9x \\ \therefore \: {x}^{2} + 40x + 400 - 9x = 0 \\ \therefore \: {x}^{2} + 31x + 400 = 0 \\$

8 0

3 years ago