Pita has 12 coins in her bag there are three 1 pound coins and nine 50p coins she takes 3 coins out of the bag at random, work o
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Hey there!
<h3>Question 1</h3>Let's use 3.14 for pi during this. It'll make it a lot easier.
The volume for a cone is .
The diameter of this cone is 17.6 inches. Since the radius is half the diameter, we can find the radius by dividing this amount by 2.
17.6 ÷ 2 = 8.8
The height of this cone is 23.4 inches.
Plug the values into the equation.
Next, square 6.8 and divide 23.4 by 3. Also, replace the pi symbol with 3.14.
Multiply the numbers together.
<u>The volume of this cone is approximately 1896.66 cubic inches.</u>
<h3>Question 2</h3>Finding the volume of a trapezoidal prism can be done by finding the are of the trapezoidal face and multiplying it by the depth.
Formula for finding the area of a trapezoid is
The two bases are 10 and 34, and the height is 24.7 feet. Put these values into the equation.
Add 10 and 34, then multiply it by 24.7 and 1/2.
a = 543.4
Multiply that value by 19, which is the depth of the figure.
<u>The volume of the prism is 10324.6 cubic feet.</u>
<h3>Question 3</h3>The formula for volume of a triangular pyramid is v = 1/3ah, with a the area of the base and h the height.
The formula for the area of an equilateral triangle, which is the base, is
The length of the side is 12, so we can square that to get 144.
Now multiply that by to get the area of the base.
The area of the base is about 62.35 square meters.
The height of the pyramid is 20 meters. Plug that and the area of the base into the equation.
v = 1/3 x 62.35 x 20
Multiply the numbers together to get the volume.
<u>The volume of the pyramid is approximately 415.67 cubic meters.</u>
Hope this helps!
Answer:
Cuando María afirma que si unen sus dos cuartos de cartulina obtendrán el medio pliego que necesitan, esto es:
- <u>Verdadero</u>.
Step-by-step explanation:
Para entender mejor el ejercicio vamos a utilizar números cada vez que se habla de cantidades de cartulina, por lo tanto, María y Juan tienen 1/4 de cartulina cada uno, es decir, 1/4 * 2, y necesitan 1/2 pliego para poder realizar su tarea, por lo tanto, con la afirmación de María sobre unir los dos cuartos de cartulina, en caso de que sea verdadero, ocurrirá que la suma de los dos cuartos dará el medio pliego, como se muestra a continuación:
- Total de cartulina de María y Juan =
- Total de cartulina de María y Juan =
- Total de cartulina de María y Juan =
Procedemos a simplificar el fraccionario obtenido, sacando mitad tanto en el numerador como en el denominador:
- Total de cartulina de María y Juan =
- Total de cartulina de María y Juan =
- <u><em>Total de cartulina de María y Juan = </em></u>
<u><em /></u>
Como puedes ver al final, <u>la cantidad de cartulina de ambos, al ser sumada, da como resultado el 1/2 (medio) pliego que necesitan para su tarea de sociales, por lo cual la afirmación de María es correcta</u>.