Why is my meat so small?

X^2-7x=18 solve for x please show work

zloy xaker [14]

So the answer is, x1=-2, x2=9
x^2-7x=18
x^2-7x-18=0
x^2+2x-9x-18=0
x*(x+2)-9(x+2)=0
(x+2)*(x-9)=o
x+2=0
x-9=0
X=-2
X=9
I hope u understand!

3 0

3 years ago

M<3 is (3x + 4) and m<5 is (2x +11)

butalik [34]

Answer:

Part 1) Option C. Same side interior angles

Part 2) Option A. $(3x+4)+(2x+11)=180\°$

Part 3) Option B. $m$

Step-by-step explanation:

Part 1) we know that

If p and q are parallel

then

m<3 and m<5 are consecutive interior angles or Same side interior angles

and

$m$

Part 2) we know that

$m$ -----> by consecutive interior angles (supplementary angles)

we have that

$m$

so

substitute

$(3x+4)+(2x+11)=180\°$

Part 3) Find the measure of angle 5

we know that

$(3x+4)+(2x+11)=180\°$

Solve for x

$5x+15\°=180\°$

$5x=180\°-15\°$

$x=165\°/5\°=33\°$

$m$

substitute the value of x

$m$

8 0

3 years ago

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An equation ___ has one solution A. Always B. Sometimes C. Never

Doss [256]

im am pretty sure it is b.sometimes because an equation can have more then one answer

4 0

3 years ago

The right expression to calculate how much money will be in an investment account 14 years from now if you deposit $5,000 now an

Svet_ta [14]

Answer:

The expression to compute the amount in the investment account after 14 years is: FV = [5000 ×(1.10)¹⁴] + [3000 ×(1.10)⁸].

Step-by-step explanation:

The formula to compute the future value is:

$FV=PV[1+\frac{r}{100}]^{n}$

PV = Present value

r = interest rate

n = number of periods.

It is provided that $5,000 were deposited now and $3,000 deposited after 6 years at 10% compound interest. The amount of time the money is invested for is 14 years.

The expression to compute the amount in the investment account after 14 years is,

$FV=5000[1+\frac{10}{100}]^{14}+3000[1+\frac{10}{100}]^{14-6}\\FV=5000[1+0.10]^{14}+3000[1+0.10]^{8}$

The future value is:

$FV=5000[1+0.10]^{14}+3000[1+0.10]^{8}\\=18987.50+6430.77\\=25418.27$

Thus, the expression to compute the amount in the investment account after 14 years is: FV = [5000 ×(1.10)¹⁴] + [3000 ×(1.10)⁸].

4 0

3 years ago

Total profit P is the difference between total revenue R and total cost C. Given the following total-revenue and total-cost fu

gavmur [86]

Answer:

The profit function is:

$P(x)=-x^2+1280x-3300$

The maximum value is 406, 300 occurring when x = 640.

Step-by-step explanation:

The revenue function is:

$R(x)=1300x-x^2$

And the cost function is:

$C(x)=3300+20x$

Then the total profit function will be:

$P(x)=R(x)-C(x)=(1300x-x^2)-(3300+20x)=-x^2+1280x-3300$

This is a quadratic function.

Therefore, the maximum value of the total profit will occur at its vertex point.

The vertex of a quadratic is given by:

$\displaystyle \Big(-\frac{b}{2a}, f\Big(-\frac{b}{2a}\Big)\Big)$

In this case, a = -1, b = 1280, and c = -3300.

Then the point at which the maximum profit occurs is at:

$\displaystyle x=-\frac{1280}{2(-1)}=640$

And the maximum profit will be:

$P(640)=-(640)^2+1280(640)-3300=406300$

5 0

3 years ago

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