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3 years ago

2) A square and a rectangle have the same perimeter. The square has a side length of 6 x units. The

Mathematics

1 answer:

Romashka-Z-Leto [24]3 years ago

3 0

Answer:

The value of X should be 8

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Using the arithmetic sequence 7 10 13 16 find the 6th term of the sequence

algol13

22 is the correct answer

8 0

2 years ago

7 × (–3) × (–2)^2 =

skad [1K]

<span>7 × (–3) × (–2)^2
= </span>-21 × 4
= - 84

Hope it helps

5 0

3 years ago

Read 2 more answers

the pitch, or frequency, of a vibrating string varies directly with the square root of the tension. if a string vibrates at a fr

Naily [24]

$\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\
\begin{array}{llll}
\stackrel{frequency}{f}\textit{ of a vibrating string varies directly}\\
\qquad \qquad \textit{with the square root of the tension }\stackrel{tension}{t}
\end{array}$

$\bf f=k\sqrt{t}\quad \textit{we also know that }
\begin{cases}
f=300\\
t=8
\end{cases}\implies 300=k\sqrt{8}
\\\\\\
\cfrac{300}{\sqrt{8}}=k\implies \cfrac{300}{\sqrt{2^2\cdot 2}}=k\implies \cfrac{300}{2\sqrt{2}}=k\implies \cfrac{150}{\sqrt{2}}=k
\\\\\\
\textit{and we can \underline{rationalize} it to }\cfrac{150\sqrt{2}}{2}\implies 75\sqrt{2}=k$

$\bf thus\qquad f=\stackrel{k}{75\sqrt{2}}\sqrt{t}\implies \boxed{f=75\sqrt{2t}}\\\\
-------------------------------\\\\
\textit{now, when t = 72, what is \underline{f}?}\qquad f=75\sqrt{2(72)}$

5 0

3 years ago

Read 2 more answers

Ella and jade both ran a marathone ella finished 4 hours 6 mins and 13 seconds jade finished in 4 hours and 3 mins and 18 second

spin [16.1K]

Answer:

Jade is faster than Ella by 2 minutes and 55 seconds.

Step-by-step explanation:

We are told that Ella and Jade both ran a marathon. Ella finished marathon in 4 hours 6 mins and 13 seconds. Jade finished marathon in 4 hours and 3 mins and 18 seconds.

We can write 4 hour 6 minutes 13 seconds as 4 hour 5 minutes 73 seconds. 1 minute has been borrowed to the seconds side, and seconds become 13+60 = 73 seconds.

We can see that Ella took more time than Jade. Let us find how much more time Ella took than Jade by subtracting time taken by Jade from time taken by Ella.

$4\text{ hr }5\text{ min }73\text{ sec }-4\text{ hr }3\text{ min }18{ sec }= 2\text{ min }55\text{ sec }$

We can see that Jade took 2 minute and 55 seconds less than Ella , therefore, Jade was faster than Ella by 2 minutes 55 seconds.

4 0

3 years ago

WILL GIVE BRAINLIEST

myrzilka [38]

Answer:

$\sqrt{11}$

Step-by-step explanation:

The square root of 11 is 3.31... this could be the answer.

3 0

2 years ago