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Scrat [10]
2 years ago
14

Simplify 5.142857142857143

Mathematics
2 answers:
Sergeeva-Olga [200]2 years ago
6 0
The answer is 5 because the 1 in the tenths place is less than 5 so it tells the digit in the ones place to stay the same.
faust18 [17]2 years ago
6 0

Answer:

pie squared

Step-by-step explanation:

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Y = - |x+3| - 4<br><br><br> It needs to be graphed, please help!
MA_775_DIABLO [31]

Answer:

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Which of the following sets of data will have the smallest Standard Deviation?
uranmaximum [27]

Answer: D

Step-by-step explanation:

Standard Deviation σ2 =

Σ(xi - μ)2/N

=(1 - 5.3)2 + ... + (9 - 5.3)2/10

=68.1/10

= 6.81

σ = √6.81

= 2.60959767014

B) σ2 =

Σ(xi - μ)2/N

=(3 - 61.7)2 + ... + (99 - 61.7)2/10

=58414.1/10

= 5841.41

σ = √5841.41

= 76.429117488036

C) (1 - 11.4)2 + ... + (1 - 11.4)2/10

=8758.4/10

= 875.84

σ = √875.84

= 29.59459410095

D) (79 - 79)2 + ... + (79 - 79)2/10

=0/10

= 0

σ = √0

= 0

I hope this helps, mark as Brainliest please.

6 0
3 years ago
Plz Help! I need this ASAP! I will give brainlest!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
viktelen [127]

7)  164.26

8)77.08

9)2405.364

steps for 7) attached

steps for 8)

7 0
3 years ago
I need help on this question
inna [77]

Hello!

You always think of these graphs out of 100%. As you can see, the blue takes up about half of he graph. Half of 100 is 50.

Therefore, our answer is D) 50%

I hope this helps!

5 0
3 years ago
Read 2 more answers
A band of 17 pirates stole a sack of gold coins. When they tried to divide the fortune into equal portions, 3 coins remained. In
mamaluj [8]

Answer:

The least number of coins that could have been stolen is 3,930.

Step-by-step explanation:

In the beginning, there are N coins to be distributed among 17 pirates, and we know that if we divide evenly these coins, there are 3 coins remaining.

Then we can write the total number of coins as a multiple of 17 plus 3.

N = 17*k + 3

where k is an integer.

After that, a pirate is killed, so now we have 16 pirates, and now there are 10 coins left, so now we can write N as a multiple of 16 plus 10:

N = 16*j + 10

where j is an integer.

Finally, having 15 pirates, the total number of coins can be divided evenly, then N is a multiple of 15

N = 15*m

where m is an integer.

So we have these 3 equations:

N = 17*k + 3

N = 16*j + 10

N = 15*m

So we can express equations like:

15*m = 16*j + 10

15*m = 17*k + 3

Where we need to find solutions such that both of these variables are integers.

For the first one we can write:

15*m - 16*j = 10

One way to do it, is to write this like a linear equation:

m = (16*j + 10)/15

Graph this, and find the pairs of points in the line that have bot integer values, or we can just find some values of j such that:

16*j + 10 is a multiple of 15.

For example, with j = 5 we have:

m = (16*5 + 10)/15 = 6

so j = 5 and m = 6 is a possible solution.

Now if we use m = 6 in the other equation:

15*m = 17*k + 3

we can see if k is also an integer:

k = (15*m - 3)/17

replacing m by 6:

k = (15*6 - 3)/17 = 5.1

This solution does not work.

Let's find others:

if j = 20  (at this point we already know that the possible values of j "jump" by 15 units, like 5 + 15 = 20) then:

m = (16*20 + 10)/15 = 22

Then:

j = 20 and  m = 22 is another solution.

Same as before, let's use m = 22 in the equation for k:

k = (15*22 - 3)/17 = 19.2

Let's find another solution for m.

if  j = 35

m = (16*35 + 10)/15 = 38

Using this value of m in the k equation we get:

k = (15*35 - 3)/17 = 33.4

Let's find another solution for m.

if we take j = 50 we get:

m = (15*50 + 10)/15 = 54

Using this in the k equation we get:

k = (15*54 - 3)/17 = 47.5

Eventually, for j = 5  + 15*16 = 245 we get:  (arrived by iteration, just try each time using the previous value of j plus 15)

m = (16*245 + 10)/15 = 262

replacing this in the k equation we can find:

k = (15*262 - 3)/17 = 231.

So the first solution is:

j = 245, m = 262, k = 231

Then:

N = 262*15 = 3,930

The least number of coins that could have been stolen is 3,930.

7 0
2 years ago
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