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Kruka [31]
2 years ago
15

The ratio of boys to girls in the gym is 4 to 5. There are 20 girls in the gym.

Mathematics
2 answers:
11Alexandr11 [23.1K]2 years ago
8 0
16:20 because u multiply them by 4 each
kirza4 [7]2 years ago
3 0

Answer:

36 is the answer you are looking for

Step-by-step explanation:

hope this helps

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Please help me with this radical expression​
LenaWriter [7]

Answer:

a. ⁴√x³

d. ¹²√x⁹

Step-by-step explanation:

First, simplify 9⁄12 to ¾. Then, according to the Definition of Rational Exponents [part II], ⁿ√aᵐ = aᵐ\ⁿ, you set your denominator equal to the root, and your numerator becomes your exponent, keeping your base INSIDE the radical.

I am joyous to assist you anytime.

6 0
3 years ago
How do u graph linear inequality
amm1812
There are three steps

1 rearrange the equation so "y" is on the left and everything else is on the right

2 plot the "y=" line (make it a solid line for y< or y> and a dashed line for y< or y>)

3 shade above the line for a "greater than" (y> or y>) line under that or below the line for a less than (y< or y< line under it)
6 0
3 years ago
PLZ I NEED ANSWERS NOW!!!! {(-1, 2), (0, 2), (5, 2)} is a function. TrueFalse
KIM [24]

Answer:

True

Step-by-step explanation:

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7 0
3 years ago
Can anyone help me with my homework
damaskus [11]
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6 0
3 years ago
Verify the following identity and show steps<br><br> (Cos2 θ)/(1+sin2 θ)= (cot θ-1)/(cot θ+1)
Paul [167]

Answer:

Verified below

Step-by-step explanation:

We want to show that (Cos2θ)/(1 + sin2θ) = (cot θ - 1)/(cot θ + 1)

In trigonometric identities;

Cot θ = cos θ/sin θ

Thus;

(cot θ - 1)/(cot θ + 1) gives;

((cos θ/sin θ) - 1)/((cos θ/sin θ) + 1)

Simplifying numerator and denominator gives;

((cos θ - sin θ)/sin θ)/((cos θ + sin θ)/sin θ)

This reduces to;

>> (cos θ - sin θ)/(cos θ + sin θ)

Multiply top and bottom by ((cos θ + sin θ) to get;

>> (cos² θ - sin²θ)/(cos²θ + sin²θ + 2sinθcosθ)

In trigonometric identities, we know that;

cos 2θ = (cos² θ - sin²θ)

cos²θ + sin²θ = 1

sin 2θ = 2sinθcosθ

Thus;

(cos² θ - sin²θ)/(cos²θ + sin²θ + 2sinθcosθ) gives us:

>> cos 2θ/(1 + sin 2θ)

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5 0
2 years ago
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