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NISA [10]
3 years ago
14

What is an equation of the line that passes through the point (-1, 4) and is parallel

Mathematics
1 answer:
vesna_86 [32]3 years ago
3 0

Answer:

The answer is

<h2>y + 2x = 2</h2>

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

To find the equation of the parallel line we must first find the slope of the original line

The original line is 2x + y = 1

We must first write the equation in the general form above

That's

y = - 2x + 1

Comparing with the general equation above

Slope = - 2

Since the lines are parallel their slope are also the same

Slope of parallel line = - 2

So the equation of the line using point

( - 1 , 4) and slope - 2 is

<h3>y - 4 =  - 2(x + 1) \\ y - 4 =  - 2x - 2 \\ y + 2x =  - 2 + 4</h3>

We have the final answer as

<h3>y + 2x = 2</h3>

Hope this helps you

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According to the empirical (69-95-99.7) rule, if a random variable z has a standard normal distribution, then approximately 95%
Dmitry_Shevchenko [17]

Using z-scores, it is found that the value of z is z = 1.96.

-----------------------------

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula, which for a measure X, in a distribution with mean \mu and standard deviation \sigma, is given by:  

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • Each z-score has an associated p-value, which is the percentile.

  • The normal distribution is symmetric, which means that the middle 95% is between the <u>2.5th percentile and the 97.5th percentile</u>.
  • The 2.5th percentile is Z with a p-value of 0.025, thus Z = -1.96.
  • The 97.5th percentile is Z with a p-value of 0.975, thus Z = 1.96.
  • Thus, the value of Z is 1.96.

A similar problem is given at brainly.com/question/16965597

7 0
2 years ago
Based only on the information given in the diagram, which congruence
Wewaii [24]

Answer:

Option B

Option E

Step-by-step explanation:

By the use of following postulates we can prove the two right triangles to be congruent.

1). HA - [Equal hypotenuse and an cute angles]

2). LL - [Two legs should be equal]

3). LA - [One leg and one angle must be equal]

4). ASA - [Two angles and the side containing these angles should be equal]

In the given right triangles,

1). OJ ≅ IL

2). ∠O ≅ ∠I

3). ∠J ≅ ∠L

Therefore, two postulates HA, ASA will be applicable for the congruence of the two triangles given.

Options A and E will be the answer.

3 0
4 years ago
Read 2 more answers
The axis of symmetry for the graph of the function f start bracket x end bracket equals one-quarter x square plus b x plus 10 is
zimovet [89]

The value of b is -3.

<h3>What is axis of symmetry?</h3>

Axis of symmetry is a line that divides an object into two halves,thereby creation a mirror like reflection of either side of the object.

Now the given function is,

f(x) = 1/4 x^2 bx + 10

and axis of symmetry is at x = 6

Now the quadratic function in standard form is given as,

f(x) = a x^2 bx + c

By comprison we get,

a = 1/4

c = 10

Since axis of symmetry is a vertical line

x = -b/2a

Therefore,

6 = -b/2*(1/4)

-b = 6*2*(1/4)

or, b = -12/4

or, b = -3

Hence,The value of b is -3.

More about axis of symmetry :

brainly.com/question/3514150

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3 0
2 years ago
How many places do you need to move the decimal to the left to write the
NikAS [45]

Answer: 6 x 10^12

Step-by-step explanation:

Move the decimal to the left so there is one non-zero digit number left of the decimal point. This will be the exponent placed on 10

3 0
3 years ago
A teacher places n seats to form the back row of a classroom layout. Each successive row contains two fewer seats than the prece
Alex_Xolod [135]

Answer:

The number of seat when n is odd S_n=\frac{n^2+2n+1}{4}

The number of seat when n is even S_n=\frac{n^2+2n}{4}

Step-by-step explanation:

Given that, each successive row contains two fewer seats than the preceding row.

Formula:

The sum n terms of an A.P series is

S_n=\frac{n}{2}[2a+(n-1)d]

    =\frac{n}{2}[a+l]

a = first term of the series.

d= common difference.

n= number of term

l= last term

n^{th} term of a A.P series is

T_n=a+(n-1)d

n is odd:

n,n-2,n-4,........,5,3,1

Or we can write 1,3,5,.....,n-4,n-2,n

Here a= 1 and d = second term- first term = 3-1=2

Let t^{th} of the series is n.

T_n=a+(n-1)d

Here T_n=n, n=t, a=1 and d=2

n=1+(t-1)2

⇒(t-1)2=n-1

\Rightarrow t-1=\frac{n-1}{2}

\Rightarrow t = \frac{n-1}{2}+1

\Rightarrow t = \frac{n-1+2}{2}

\Rightarrow t = \frac{n+1}{2}

Last term l= n,, the number of term =\frac{ n+1}2, First term = 1

Total number of seat

S_n=\frac{\frac{n+1}{2}}{2}[1+n}]

    =\frac{{n+1}}{4}[1+n}]

     =\frac{(1+n)^2}{4}

    =\frac{n^2+2n+1}{4}

n is even:

n,n-2,n-4,.......,4,2

Or we can write

2,4,.......,n-4,n-2,n

Here a= 2 and d = second term- first term = 4-2=2

Let t^{th} of the series is n.

T_n=a+(n-1)d

Here T_n=n, n=t, a=2 and d=2

n=2+(t-1)2

⇒(t-1)2=n-2

\Rightarrow t-1=\frac{n-2}{2}

\Rightarrow t = \frac{n-2}{2}+1

\Rightarrow t = \frac{n-2+2}{2}

\Rightarrow t = \frac{n}{2}

Last term l= n, the number of term =\frac n2, First term = 2

Total number of seat

S_n=\frac{\frac{n}{2}}{2}[2+n}]

    =\frac{{n}}{4}[2+n}]

     =\frac{n(2+n)}{4}

    =\frac{n^2+2n}{4}  

4 0
3 years ago
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