Question

The four corners of a rectangular city block are located at (-5, -2).(-5,9). (9,9), and

Answer 1

Answer:

500 metres

Step-by-step explanation:

As per the question statement:

Randy walks all the way around the block and stops when he gets back to where he started.

Distance of 1 unit is 10m.

Please refer to the image attached:

$A(-5,-2),\ B(9,-2),\ C(9,9),\ D(-5,9)$

Let us assume that he starts from point A and then moves towards point B, then towards point C and then D and finally reaches point A back.

$A \rightarrow B \rightarrow C \rightarrow D \rightarrow A$

While walking from A to B, he walks parallel to x-axis for 9 - (-5) units i.e. 14 units.

$Distance = 14 \times 10\\\Rightarrow 140m$

While walking from B to C, he walks parallel to y-axis for 9 - (-2) units i.e. 11 units.

$Distance = 11 \times 10\\\Rightarrow 110m$

Similarly, C to D, he walks parallel to x-axis for 9 - (-5) units i.e. 14 units.

$Distance = 14 \times 10\\\Rightarrow 140m$

Similarly, D to A, he walks parallel to y-axis for 9 - (-2) units i.e. 11 units.

$Distance = 11 \times 10\\\Rightarrow 110m$

Total distance traveled is 110 + 140 + 110 + 140 = 500 metres.