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(3a^4 * b^-2) * (2a^7 * b^-1)
= 6*a^(4+7)*b^(-2-1)
= 6*a^11*b^-3
Answer:
Not sure sorry,but can you please help me on the following:
Step-by-step explanation:
Length of a rectangle is 5 cm longer than the width. Four squares are constructed outside the rectangle such that each of the squares share one side with the rectangle. The total area of the constructed figure is 120 cm2. What is the perimeter of the rectangle?
To get the vertex of the parabola we proceed as follows;
y=-7(x-4)^2-5
The above can be written as:
y=-7x^2+56x-117
The values of a,b and c are:
a=-7, b=56 and c=-117
x=-b/(2a)
x=-56/(-7*2)=4
but;
y=-7x^2+56x-117
y=-7(4)^2+56(4)-117
y=-5
Thus;
x=4 and y=-5
The vertex will be at point (4,-5)
5√2 · 9√6
Simplify.
5 × 9 √ 2 x 6 ⇒ Multiply 2 × 6.
5 × 9 √12
Simplify √12 to 2√3.
5 × 9 × 2√3 ⇔ Multiply
90√3
Therefore, the <u>correct alternative</u> is <u>option "B".</u>
