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3 years ago

Determine the distance between the points (-2,3) and (5,- 3).

1 answer:

5 0

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-2}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{-3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[5-(-2)]^2+[-3-3]^2}\implies d=\sqrt{(5+2)^2+(-6)^2} \\\\\\ d=\sqrt{49+36}\implies d=\sqrt{85}\implies d \approx 9.22$

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Step-by-step explanation:

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3 years ago

Find derivative problem Find B’(6)

dalvyx [7]

Answer:

$B^\prime(6) \approx -28.17$

Step-by-step explanation:

We have:

$\displaystyle B(t)=24.6\sin(\frac{\pi t}{10})(8-t)$

And we want to find B’(6).

So, we will need to find B(t) first. To do so, we will take the derivative of both sides with respect to x. Hence:

$\displaystyle B^\prime(t)=\frac{d}{dt}[24.6\sin(\frac{\pi t}{10})(8-t)]$

We can move the constant outside:

$\displaystyle B^\prime(t)=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)]$

Now, we will utilize the product rule. The product rule is:

$(uv)^\prime=u^\prime v+u v^\prime$

We will let:

$\displaystyle u=\sin(\frac{\pi t}{10})\text{ and } \\ \\ v=8-t$

Then:

$\displaystyle u^\prime=\frac{\pi}{10}\cos(\frac{\pi t}{10})\text{ and } \\ \\ v^\prime= -1$

(The derivative of u was determined using the chain rule.)

Then it follows that:

$\displaystyle \begin{aligned} B^\prime(t)&=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)] \\ \\ &=24.6[(\frac{\pi}{10}\cos(\frac{\pi t}{10}))(8-t) - \sin(\frac{\pi t}{10})] \end{aligned}$

Therefore:

$\displaystyle B^\prime(6) =24.6[(\frac{\pi}{10}\cos(\frac{\pi (6)}{10}))(8-(6))- \sin(\frac{\pi (6)}{10})]$

By simplification:

$\displaystyle B^\prime(6)=24.6 [\frac{\pi}{10}\cos(\frac{3\pi}{5})(2)-\sin(\frac{3\pi}{5})] \approx -28.17$

So, the slope of the tangent line to the point (6, B(6)) is -28.17.

5 0

3 years ago

What is the equation of the line that passes through the points (1,5) and (0,3)?

Pavlova-9 [17]

Answer:

y=2x+3

Step-by-step explanation:

first use the y2-y1/x2-x1 then use y=mx+b after

plug in 3 for y2 and 5 for y1

then plug in 0 for x2 and 1 for x1

$\frac{3-5}{0-1}$ = $\frac{-2}{-1} =2$ and 2 is ur slope

___________________

now use y=mx+b

i usually use the first point but u can u anyone u want

plug in 1 for x

plug in 5 for y

and plug in 2 for m

5=2(1)+b

5=2+b

subtract 2 on both sides

5-2=3

3=b and b is ur y-intercept

y=2x+3

hope this helps

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3 years ago

What two numbers add to +5 and have a product of -3?

Tasya [4]

They don't come out even.
As rounded decimals, the two numbers are

5.54138... and -0.54138...

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3 years ago

The length of a rectangle is 4 cm longer than the width, The perimeter is 80 cm. Find the length and the width. Substition Metho

MrRa [10]

Answer: Length = l

Width = w

2l + 2w = 80cm

l+w = 40cm

l = w+4

w+4 + w = 40cm

2w + 4 = 40cm

2w = 36cm

w = 18cm

l = 22cm

jd3sp4o0

Step-by-step explanation:

6 0

3 years ago

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