Question

Some fertilizer blends contain magnesium nitrate (MgNO3). Suppose that a chemist has 1.24 liters of a 2.13 M solution of magnesium nitrate. If the chemist dilutes the solution to 1.60 M, what is the volume of the new solution? Express your answer to three significant figures. The volume of the new solution is liters.

Answer 1

1.65 litres is your answer

Answer 2

Answer : The volume of new solution is, 1.65 liter

Solution :

According to the dilution,

$M_1V_1=M_2V_2$

where,

$M_1$ = molarity of magnesium nitrate solution = 2.13 M

$V_1$ = volume of magnesium nitrate solution = 1.24 L

$M_2$ = molarity of new solution = 1.60 M

$V_2$ = volume of new solution = ?

Now put all the given values in the above law, we get the volume of new solution.

$(2.13M)\times (1.24L)=(1.60M)\times V_2$

$V_2=1.65L$

Therefore, the volume of new solution is, 1.65 liter