Answer:
Explanation:
Let's consider the following reaction.
CO(g) + 2 H₂(g) ⇌ CH₃OH(g)
The equilibrium constant (Kc) is <em>the products of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentration of the reactants raised to their stoichiometric coefficients.</em>
If you wanted to calculate [CH₃OH], suppose that the molar concentrations for CO and H₂ at equilibrium are [CO] = 0.04 M and [H₂] = 0.08 M. The concentration of methanol at equilibrium is:
<u>Answer:</u> The equilibrium constant for the given reaction is 0.8
<u>Explanation:</u>
Equilibrium constant is defined as the ratio of concentration of the products raised to the power its stoichiometric coefficients to the concentration of reactants raised to power its stoichiometric coefficient. It is represented as
For the general equation:
The equilibrium constant is represented as:
For the given chemical equation:
for this equation is given by:
Concentration at equilibrium of
Putting values in above equation, we get:
Hence, the equilibrium constant for the given chemical reaction is 0.8
Answer:gamma rays
Explanation: your welcome