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1 year ago

What is one takeaway you have about future sea levels rising ?

Chemistry

2 answers:

Galina-37 [17]1 year ago

7 0

Answer:

Our world will never be the same. Our beaches will be submerged, many towns, cities, states, and even countries will be partially if not completely submerged. All these human cities being flooded will kill thousands of people, pollute the ocean, and lose billions of dollars.

Explanation:

jonny [76]1 year ago

5 0

Based on their new scenarios, global sea level is very likely to rise at least 12 inches (0.3 meters) above 2000 levels by 2100 even on a low-emissions pathway. On future pathways with the highest greenhouse gas emissions, sea level rise could be as high as 8.2 feet (2.5 meters) above 2000 levels by 2100

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You have a sample of 75.6 g of C3H8. How many moles of C3H8 are in the sample?

dsp73

The number of moles that are contained in the given mass of propane ( $C_3H_8$ is 1.7143 moles.

<u>Given the following data:</u>

Mass of propane = 75.6 grams.

<u>Scientific data:</u>

The molar mass of propane = 44.1 g/mol.

To calculate the number of moles that are contained in the given mass of propane ( $C_3H_8$ ):

<h3>How to calculate the moles of a compound.</h3>

In this exercise, you're required to determine the number of moles of propane that are contained in the given sample:

Mathematically, the number of moles contained in a chemical compound is given by this formula:

$Number\;of\;moles = \frac{mass}{molar\;mass}$

Substituting the given parameters into the formula, we have;

$Number\;of\;moles = \frac{75.6}{44.1}$

Number of moles = 1.7143 moles.

Read more on number of moles here: brainly.com/question/3173452

3 0

2 years ago

A particular reaction, A- products, has a rate that slows down as the reaction proceeds. The half-life of the reaction is found

Thepotemich [5.8K]

Explanation:

Half life of zero order and second order depends on the initial concentration. But as the given reaction slows down as the reaction proceeds, therefore, it must be second order reaction. This is because rate of reaction does not depend upon the initial concentration of the reactant.

a. As it is a second order reaction, therefore, doubling reactant concentration, will increase the rate of reaction 4 times. Therefore, the statement a is wrong.

b. Expression for second order reaction is as follows:

$\frac{1}{[A]} =\frac{1}{[A]_0} +kt$

the above equation can be written in the form of Y = mx + C

so, the plot between 1/[A] and t is linear. So the statement b is true.

Expression for half life is as follows:

$t_{1/2}=\frac{1}{k[A]_0}$

As half-life is inversely proportional to initial concentration, therefore, increase in concentration will decrease the half life. Therefore statement c is wrong.

Plot between A and t is exponential, therefore there is no constant slope. Therefore, the statement d is wrong

8 0

2 years ago

A force between charged objects

Darya [45]

Answer:

Coulomb's law, mathematical description of the electric force between charged objects. Formulated by the 18th-century French physicist Charles-Augustin de Coulomb, it is analogous to Isaac Newton's law of gravity.

Explanation:

Soo yeah I think this can help you

3 0

2 years ago

A sample of gas contains 0.1700 mol of OF2(g) and 0.1700 mol of H2O(g) and occupies a volume of 19.5 L. The following reaction t

andreev551 [17]

Answer: The volume of the sample after the reaction takes place is 29.25 L.

Explanation:

The given reaction equation is as follows.

$OF_{2}(g) + H_{2}O(g) \rightarrow O_{2}(g) + 2HF(g)$

So, moles of product formed are calculated as follows.

$\frac{3}{2} \times 0.17 mol \\= 0.255 mol$

Hence, the given data is as follows.

$n_{1}$ = 0.17 mol, $n_{2}$ = 0.255 mol

$V_{1}$ = 19.5 L, $V_{2} = ?$

As the temperature and pressure are constant. Hence, formula used to calculate the volume of sample after the reaction is as follows.

$\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}$

Substitute the values into above formula as follows.

$\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\\frac{19.5 L}{0.17 mol} = \frac{V_{2}}{0.255 mol}\\V_{2} = \frac{19.5 L \times 0.255 mol}{0.17 mol}\\= \frac{4.9725}{0.17} L\\= 29.25 L$

Thus, we can conclude that the volume of the sample after the reaction takes place is 29.25 L.

8 0

2 years ago

A carboxylic acid is named in the IUPAC system by replacing the -e in the name of the parent alkane with

serg [7]

A carboxylic acid is named in the IUPAC system by replacing the -e in the name of the parent alkane with -<u>oic acid</u>

<u></u>

<h3>What is carboxylic acid?</h3>

Carboxylic acid is an organic acid that contains a carboxyl group (C(=O)OH) attached to an R-group. The general formula of a carboxylic acid is R−COOH or R−CO2H, with R referring to the alkyl, alkenyl, aryl, or other group. Carboxylic acids occur widely. Important examples include the amino acids and fatty acids. Deprotonation of a carboxylic acid gives a carboxylate anion.

Carboxylic acids are commonly identified by their trivial names. They often have the suffix -ic acid. IUPAC-recommended names also exist; in this system, carboxylic acids have an -oic acid suffix. For example, butyric acid (C3H7CO2H) is butanoic acid by IUPAC guidelines. For nomenclature of complex molecules containing a carboxylic acid, the carboxyl can be considered position one of the parent chain even if there are other substituents, such as 3-chloropropanoic acid. Alternately, it can be named as a "carboxy" or "carboxylic acid" substituent on another parent structure, such as 2-carboxyfuran.

Learn more about carboxylic acid

brainly.com/question/26855500

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5 0

1 year ago