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yuradex [85]
3 years ago
5

A quarterback throws a pass from the 10-yard line, 2 yards from the sideline. A wide received catches the pass on the 64-yard li

ne, 8 yards from the same sideline. To the nearest whole yard, how long is the pass?
Mathematics
1 answer:
satela [25.4K]3 years ago
4 0
I believe it is 60 yards
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Sean has some candy bars that he wants to give away. He is going to give each person \dfrac18 8 1 ​ start fraction, 1, divided b
Afina-wow [57]

Answer:

22 people

Step-by-step explanation:

Sean has 2 3/4 candy bars. That is 11/4 candy bars.

He wants to give out 1/8 candy bars.

The number of people that will get candy is:

\frac{11}{4} / \frac{1}{8}\\ \\= \frac{\frac{11}{4} }{\frac{1}{8}} \\\\\frac{11}{4} * \frac{8}{1} \\\\22

22 people can get candy.

8 0
3 years ago
Read 2 more answers
Is (-3,-9) a solution of the equation y = 3x ?<br> O YES<br> O NO<br> O NOT A SOLUTION
melomori [17]

Answer:

Yes, (-3, -9) is a solution.

Step-by-step explanation:

y = 3x   (-3,-9)

-9 = 3(-3)

-9 = -9

4 0
3 years ago
A spinner is divided into 20 equal sections. What is the probability of the spinners pointer landing on section 5
BaLLatris [955]
One over twenty is the probability


4 0
4 years ago
The average of your first 6 tests is 82. If your test average after your seventh test is an 80.5, what did you score on the seve
mart [117]
So average is  of the first 6 tests is 82   well that means 

(test1 + test2+ test3+ test4 + test5+test6)/6 = 82

so now let do some cross multiplliying 

test1 + test2 + test3 + test 4 + test5 +test6 = 82*6

test1 + test2 + test3 + test 4 + test5 +test6  = 492

now lets see if we can find that 7th test score

(test1 + test2 + test3 + test4 + test5 +test6 + test7)/7 = 80.5

So look we found test1 + test2 + test3 + test4 + test5 +test6 to be 492 so lets substitute. 

(492 + test7 )/7 = 80.5

test7 = (80.5*7)-492 = 71.5 



7 0
3 years ago
The Byrds. You have 16 new CDs to put on your empty five-shelf CD rack. Can you place the CDs so that each shelf contains three
bulgar [2K]
If each shelf is to contain exactly 3 new CDs and there are only 5 shelves, only 15 can be placed in the rack. So, the answer to the second question is no. The same goes for the first question as placing 3 or fewer CDs to the shelves will make the rack insufficient for the CDs. 
5 0
4 years ago
Read 2 more answers
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