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2 years ago

Which point is on the circle centered at the origin with a radius of 5 units?

Mathematics

2 answers:

egoroff_w [7]2 years ago

5 0

Answer:2, square root of 21 just took the test!

Step-by-step explanation:

Aleonysh [2.5K]2 years ago

3 0

Answer:

(2,√21)

Step-by-step explanation:

The circle centered at the origin has equation:

${x}^{2} + {y}^{2} = 25$

Any point that satisfies this equation lie on this circle.

When x=2, we substitute and solve for y.

${2}^{2} + {y}^{2} = 25 \\ 4 + {y}^{2} = 25 \\ {y}^{2} = 25 - 4 \\ {y}^{2} = 21$

Take square root to get:

$y = \pm \sqrt{21}$

Therefore (2,-√21) and (2,√21) are on this circle.

From the options, (2,√21) is the correct answer

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3 years ago

State which of the following sets of ordered pairs represent a function.

zalisa [80]

Answer:

Option (D) is correct.

Step-by-step explanation:

A function can be termed as a process from a set of x values to a set of possible y-values where each x-value relates to exactly one y-value.

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2 years ago

PLEASE HELP I've tried everything 30 points!

Luda [366]

Answer:

(x+2)1x-8)=0

x=-2 or x=8

Step-by-step explanation:

The given quadratic expression is

$2 {x}^{2} - 12x - 32$

We equate this expression to zero to get:

$2 {x}^{2} - 12x - 32 = 0$

Let us divide through by 2 to get:

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Split the middle term to get:

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2 years ago

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tatiyna

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Step-by-step explanation:

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