Can you please show me how to do this?

Mathematics

1 answer:

LenaWriter [7]3 years ago

8 0

If you continue the top ray down to the lower our the two lines you create an angle that it's an exterior angle of a triangle and it's also a corresponding angle to the 110° angle. since corresponding angles are congruent this angles is also 110°. this angle makes a linear pair with the angle to it left, the lower right angle on the triangle. linear pairs add to 180° so the angle has to be 70°. the lower left angle of this triangle is given as 37°. since the 3 angles of a triangle must add to 180° , the top angle has to be 180-(70+37)=73. since the top angle of the triangle makes a linear pair with the angle in question, our angle has to be 180-73=107°

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SOLVE THIS VERY IMPORTANT QUESTION

tester [92]

Answer:

Step-by-step explanation:

$\dfrac{Cos \ A}{1 + Sin \ A}=\dfrac{Cos \ A *(1-Sin \ A)}{(1+Sin \ A)(1 - Sin \ A)}\\\\\\=\dfrac{Cos \ A *(1 - Sin \ A)}{1^{2}-Sin^{2} \ A}\\\\\\=\dfrac{Cos \ A *(1 - Sin \ A)}{Cos^{2} \ A}\\\\\\=\dfrac{1-Sin \ A}{Cos \ A}$ ------(I)

$LHS =\dfrac{Cos \ A}{1+Sin \ A}+\dfrac{1+Sin \ A}{Cos \ A}\\\\\\ = \dfrac{1-Sin \A}{Cos \ A}+\dfrac{1+Sin \ A}{Cos \ A} \ [from \ equation \ (I)]\\\\\\=\dfrac{1-Sin \ A + 1 - Sin \ A}{Cos \ A}\\\\=\dfrac{2}{Cos \ A}\\\\\\=2*Sec \ A = RHS$