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geniusboy [140]
3 years ago
9

Wilma bought 4 boxes of Crunch-a-lot cereal. One out of every 5 boxes has a coupon for a free box of Crunch-a-Lot. What is the p

robability that Wilma got 2 coupons?
Mathematics
1 answer:
andrew-mc [135]3 years ago
4 0

We have been given that Wilma bought 4 boxes of Crunch-a-lot cereal.

Further, we know that one out of every 5 boxes has a coupon for a free box of Crunch-a-Lot. We need to figure out the probability that Wilma got 2 coupons?

This question is based on Bernoulli's Trials. We know that probability for r successful draws out of n trials is given by:

_{r}^{n}\textrm{C}(p)^{r}(1-p)^{n-r}

We have p=\frac{1}{5},n=4,r=2. Upon substituting these values in this formula, we get:

_{2}^{4}\textrm{C}(\frac{1}{5})^{2}(1-\frac{1}{5})^{4-2}\\
\\
6\times (\frac{1}{5})^{2}(\frac{4}{5})^{2}\\
\\
6\times \frac{1}{25}\times \frac{16}{25}\\
\\
\frac{96}{625}\approx 0.1536

This is the required probability.


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The area of a circle is 43.25cm2.<br> Find the length of the radius rounded to 2 DP.
Monica [59]

Answer:

3.71 cm

Step-by-step explanation:

Hi there!

Area of a circle equation: A=\pi r^2 where r is the radius

Plug in the area 43.25 cm²

43.25=\pi r^2

Divide both sides by π to isolate r²

\frac{43.25}{\pi} =\frac{\pi r^2}{\pi} \\\frac{43.25}{\pi}=r^2

Take the square root of both sides to isolate r

\sqrt{\frac{43.25}{\pi}} =r\\3.71=r

Therefore, the length of the radius rounded to 2 decimal points is 3.71 cm.

I hope this helps!

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