Answer:
The answer is Ce^4+ (aq) + Mn^2+ (aq) ==> Ce^3+ (aq) + Mn^3+ (aq)
Explanation:
The reaction is first order with respect to Ce^4+ and first order with respect to Mn^2+ below.
Ce^4+ (aq) + Mn^2+ (aq) ==> Ce^3+ (aq) + Mn^3+ (aq)
The rate calculation,
Ce^4+ (aq) + Mn^2+ (aq) ==> Ce^3+ (aq) + Mn^3+ (aq)
This is the catalyzed reaction.
Answer:
0.79014 J
Explanation:
According to the first law of thermodynamics:-
Where,
U is the internal energy
q is the heat
w is the work done
From the question,
q = 0 J
The expression for the calculation of work done is shown below as:
Where, P is the pressure
is the change in volume
From the question,
= 3 - 1 L = 2 L
P = 400 Pa
The expression for the conversion of pressure in Pascal to pressure in atm is shown below:
P (Pa) = 
P (atm)
Given the value of pressure = 43,836 Pa
So,
400 Pa = 
atm
Pressure = 0.0039 atm
Also, 1 atmL = 101.3 J
So,
(work is done by the system)
So,
Answer:
0.001 M OH-
Explanation:
[OH-] = 10^-pOH, so
pOH + pH = 14 and 14 - pH = pOH
14 - 11 = 3
[OH⁻] = 10⁻³ ; [OH-] = 0.001 M OH-
Answer:
4
Step-by-step explanation:
The reactions are:
Glycolysis: 1 glucose ⟶ 2 pyruvate
Link reaction: 2 × [1 pyruvate ⟶ 1 acetyl CoA]
Citric acid cycle: 2 × [1 AcetylCoA ⟶ 2 CO₂]
Now, add the reactions, cancelling species that occur on both sides of the reaction arrow,
1 glucose ⟶ <u>2 pyruvate
</u>
<u>2 pyruvate</u> ⟶ <u>2 acetyl CoA
</u>
<u>2 AcetylCoA </u>⟶ 4 CO₂
<em>Overall</em> : 1 glucose ⟶ 4 CO₂
For each mole of glucose, four molecules of CO₂ are released in the citric acid cycle.
Electrolytic cell negative
